Question

这是我从我的一个评论包中得到的一个问题，我很难过。这是描述

“返回m个字符串的列表，其中m是最长字符串的长度在strlist中，如果strlist不为空，则返回第i个字符串由strlist中每个字符串的第i个符号组成，但仅来自具有第i个符号的字符串，顺序对应于 strlist中字符串的顺序。如果strlist不包含非空字符串，则返回[]。“

这是示例

转置（['transpose'，''，'list'，'of'，'strings']）

['tlos'，'rift'，'asr'，'nti'，'sn'，'pg'，'os'，'s'，'e']

这是你要遵循的给定格式/风格

# create an empty list to use as a result
# loop through every element in the input list
# loop through each character in the string
# 2 cases to deal with here:
# case 1: the result list has a string at the correct index,
# just add this character to the end of that string
# case 2: the result list doesn't have enough elements,
# need to create a new element to store this character

我得到了“处理这里的2个案件：”部分，然后我卡住了，这是我到目前为止的事情

result = []

for index in strlist:
    for char in range (len(index)):

Answer 1

这应该有效：

def transpose(strlist):
    # create an empty list to use as a result
    result = []
    # loop through every element in the input list
    for i in range(len(strlist)):
        # loop through each character in the string
        for j in range(len(strlist[i])):
            # 2 cases to deal with here:
            if len(result) > j:
                # case 1: the result list has a string at the correct index,
                # just add this character to the end of that string
                result[j] = result[j] + strlist[i][j]
            else:
                # case 2: the result list doesn't have enough elements,
                # need to create a new element to store this character
                result.append(strlist[i][j])
    return result

print(transpose(['transpose', '', 'list', 'of', 'strings']))

输出：['tlos', 'rift', 'asr', 'nti', 'sn', 'pg', 'os', 's', 'e']

有更多pythonic方法可以实现它，但显示的代码符合您给定的格式/样式

通过检查索引是否存在将项添加到列表，然后更新

1 个答案: