Question

我使用以下RegEx：

url (blank:false, matches: /^(https?:\/\/)(?:[A-Za-z0-9]+([\-\.][A-Za-z0-9]+)*\.)+[A-Za-z]{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/)

我想添加（？i）以使所有内容不区分大小写。我该如何添加？

Answer 1

我可以确认正则表达式开头的(?i)使其不区分大小写。

无论如何，如果你的目的是减少正则表达式的长度，你可以使用groovy dollar slashy string形式。它允许你不要转义斜杠/（转义字符变为$）。

瘾：

posix chars \p{Alnum}是[0-9a-zA-Z]的紧凑等效（这样你可以避免使用(?i)。）
从char class [\-\.]中移除不需要的反斜划线 - ＆gt; [-.]（当破折号是第一个或最后一个元素并且点在字符组内始终是字面时，它不是强制性的。）
从协议部分删除不需要的圆括号

在以下版本中，我利用了美元斜线字符串和自由间距正则表达式标志(?x)的多行支持：

$/(?x)
  ^                      # start of the string
  https?://              # http:// or https://, no need of round brackets
  (                      # start group 1, have to be a non capturing (?: ... ) but is less readable
    \p{Alnum}+           # one or more alphanumeric char instead of [a-zA-Z0-9]
    ([.-]\p{Alnum}+)*   # zero or more of (literal dot or dash followed by one or more [a-zA-Z0-9])
    \.                   # a literal dot
  )+                     # repeat the group 1 one or more
  \p{Alpha}{2,40}        # between 2 and 40 alphabetic chars [a-zA-Z]
  (:[1-9][0-9]{0,4})?    # [optional] a literal colon ':' followed by at least one non zero digit till 5 digits
  (/\S*)?                # [optional] a literal slash '/' followed by zero or more non-space chars
/$

美元贬值的紧凑版本：

$/^https?://(\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}([1-9][0-9]{0,4})?(/\S*)?/$

如果你必须使用slashy版本，这是等效的：

/^https?:\/\/(?:\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/

用于测试所有这些正则表达式的代码片段：

def multiline_pattern = $/(?x)
  ^                      # start of the string
  https?://              # http:// or https://, no need of round bracket
  (                      # start group 1, have to be a non capturing (?: ... ) but is less readable
    \p{Alnum}+           # one or more alphanumeric char, instead of [a-zA-Z0-9]
    ([.-]\p{Alnum}+)*   # zero or more of (literal dot or dash followed by one or more [0-9a-zA-Z])
    \.                   # a literal dot
  )+                     # repeat the group 1 one or more
  \p{Alpha}{2,40}        # between 2 and 40 alphabetic chars [a-zA-Z]
  (:[1-9][0-9]{0,4})?    # [optional] a literal colon ':' followed by at least one non zero digit till 5 digits
  (/\S*)?                # [optional] a literal slash '/' followed by zero or more non-space chars
/$

def compact_pattern = $/^https?://(\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(/\S*)?/$

def slashy_pattern  = /^https?:\/\/(?:\p{Alnum}+([.-]\p{Alnum}+)*\.)+\p{Alpha}{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/

def url1    = 'https://www.example-test.domain.com:12344/aloha/index.html'
def notUrl1 = 'htxps://www.example-test.domain.com:12344/aloha/index.html'
def notUrl2 = 'https://www.example-test.domain.com:02344/aloha/index.html'

assert url1 ==~ multiline_pattern
assert url1 ==~ compact_pattern
assert url1 ==~ slashy_pattern

assert !( notUrl1 ==~ compact_pattern )
assert !( notUrl1 ==~ slashy_pattern  )
assert !( notUrl1 ==~ slashy_pattern  )

assert !( notUrl2 ==~ compact_pattern )
assert !( notUrl2 ==~ slashy_pattern  )
assert !( notUrl2 ==~ slashy_pattern  )

Answer 2

您将它们放在正则表达式中 - 就像在java：

中一样

groovy:000> "http://example.COM" ==~ /^(https?:\/\/)(?:[a-z0-9]+([\-\.][a-z0-9]+)*\.)+[a-z]{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/
===> false
groovy:000> "http://example.COM" ==~ /^(?i)(https?:\/\/)(?:[a-z0-9]+([\-\.][a-z0-9]+)*\.)+[a-z]{2,40}(:[1-9][0-9]{0,4})?(\/\S*)?/
===> true

Grails / Groovy正则表达式 - 如何使用（？i）使所有内容不区分大小写？

2 个答案: