我有兴趣在文件中找到最不常见的文本。
from collections import Counter
# Load the file and extract the words
lines = open("mobydick.txt").readlines()
words = [ word for l in lines for word in l.rstrip().split() ]
print 'No of words in the file:', len(words)
# Use counter to get the counts
counts = Counter( words )
print 'Least common words:'
for word, count in sorted(counts.most_common()[:-3], key=lambda (word, count): (count, word), reverse=True):
print '%s %s' % (word, count)
如何限制3个单词。它打印出一堆。
答案 0 :(得分：5)
你正在以错误的方式对列表进行切片。感受差异
print [1,2,3,4,5][:-3]
[1, 2]
print [1,2,3,4,5][-3:]
[3, 4, 5]
答案 1 :(得分：2)
var publickey = openpgp.key.readArmored(myPublicKey);
//var keyID = openpgp.packet.PublicKey(publickey).getKeyId()[0].toHex();
var keyID = openpgp.PublicKey(publickey).getKeyId()[0].toHex();
console.log(keyID);
答案 2 :(得分：2)
只需移动 <h3 >
<span>header</span>
<span ng-click="addClientClick()"
class="glyphicon glyphicon-plus pull-right btn"
title="Добавить клиента"></span>
<span class="pull-right">
<div class="input-group">
<span title="Rows per page" class="input-group-addon">
<i class="glyphicon glyphicon-th-list"></i>
</span>
<select title="Rows per page" class="form-control "
ng-model="pgtr.rowsPerPage.rows" ng-change="pgtr.rowsPerPageChange()"
ng-options="rpp for rpp in pgtr.rowsPerPageVariants " >
</select>
</div>
</span>
<span class="pull-right">
<ul class="pagination " style="padding: 0 1em 0 1em; margin: 0; ">
<li >
<a href="#" ng-click="pgtr.click('first')">1</a>
</li>
<li ng-hide="pgtr.buttons.prev.hide">
<a href="#" ng-click="pgtr.click('prev');">2</a>
</li>
<li ng-hide="pgtr.buttons.curr.hide" class="active">
<a href="#">3</a>
</li>
</ul>
</span>
</h3>
:并且正如@Joran所评论的那样，您不需要对for word, count in counts.most_common()[-3:]
print '%s %s' % (word, count)
的结果进行排序，因为它已经被订购了。