Question

我已经规范化我的表以分离beetwen tb_header和tb_detail。这是tb_repair的详细信息。

mysql> SELECT DETAIL_ID, REPAIR_ESTIMATE_ID, REMARKS, MANHOUR FROM tb_repair_detail;
+-----------+--------------------+----------------------+---------+
| DETAIL_ID | REPAIR_ESTIMATE_ID | REMARKS              | MANHOUR |
+-----------+--------------------+----------------------+---------+
|         9 |                 50 | Anda                 |   12.00 |
|        10 |                 50 | Jika                 |   10.00 |
|        11 |                 51 | ACRYLIC              |   12.00 |
|        12 |                 51 | Pembersihan exterior |   10.00 |
|        13 |                 51 | Repairing            |   10.00 |
+-----------+--------------------+----------------------+---------+
5 rows in set (0.00 sec)

现在，为了让用户更具可读性，现在我想创建一个如下所示的视图：

mysql> SELECT  a.REPAIR_ESTIMATE_ID , a.EIR_REF  ,
->  (SELECT b.NAMA FROM tb_customer_master b WHERE a.COSTUMER_ID = b.COSTUMER_ID) AS "NAMA_CUSTOMER"
-> from tb_master_repair_estimate a ;
+--------------------+---------+----------------------+
| REPAIR_ESTIMATE_ID | EIR_REF | NAMA_CUSTOMER        |
+--------------------+---------+----------------------+
|                 50 | 1545053 | APL                  |
|                 51 | 1545052 | APL                  |
+--------------------+---------+----------------------+
2 rows in set (0.00 sec)

我的问题是，我想把工时总数REPAIR_ESTIMATE_ID如何将这个工时总数放在这个视图中？我知道查询sum（）每个REPAIR ESTIMATE_ID喜欢

mysql> SELECT SUM(MANHOUR) AS TOTAL FROM tb_repair_detail a WHERE a.REPAIR_ESTIMATE_ID = 51

mysql> SELECT SUM(MANHOUR) AS TOTAL FROM tb_repair_detail a WHERE a.REPAIR_ESTIMATE_ID = 50;
+-------+
| TOTAL |
+-------+
| 22.00 |
+-------+

+-------+
| TOTAL |
+-------+
| 32.00 |
+-------+
1 row in set (0.00 sec)

但是，我如何让他们进入这些观点？

Answer 1

SELECT a.repair_estimate_id, a.eir_ref, b.nama AS nama_customer, c.total
  FROM tb_master_repair_estimate a, tb_customer_master b,
    (SELECT repair_estimate_id, SUM(manhour) AS total
      FROM tb_repair_detail
      GROUP BY repair_estimate_id) c
  WHERE a.repair_estimate_id = c.repair_estimate_id
    AND a.COSTUMER_ID = b.COSTUMER_ID

我认为，

应该给出所需的结果集。使你的视图的查询，你应该设置。

请注意条款GROUP BY repair_estimate_id，该子句会导致子查询为 SUM(manhour)的每个不同值计算repair_estimate_id。

将sum（）函数放入视图

1 个答案: