Question

所以要创建我的列表数组，我有这个

def file_processor(filename):
       #create an empty list
    cities_list = []
    try:
        file_read = open(filename, "r")
        for line in file_read:
            split_line = line.split(",")
            cities_list.append(split_line)
        file_read.close()
        return cities_list
    except IOError:
        print("File was not found.")

我需要创建一个新的列表数组，但只有0索引和第7个索引，但我所做的一切都没有用。

这是我到目前为止的重复列表

def blackWhiteSeglist(filename):
        b_w_list= []
    try:
        file_read = open(filename, "r")
        for line in file_read:
            split_line = line.split(",")
            b_w_list.append(split_line)
        file_read.close()
        for list in b_w_list:
            for line in list:
                b_w_list.pop(1:6,8:12)
        return b_w_list
    except IOError:
        print("File was not found.")

总共有13个索引（0-12），但我只需要0和7

Answer 1

只选择你需要的东西：

b_w_list.append([split_line[0], split_line[7]])

整个功能可能如下所示：

def blackWhiteSeglist(filename):
    b_w_list= []
    with open(filename, "r") as file_read:
        for line in file_read:
            split_line = line.split(",")
            b_w_list.append([split_line[0], split_line[7]])
    return b_w_list

如何从列表列表中的每个列表中删除某些索引

1 个答案: