Question

我正在尝试使用tess-two API识别android中的随机字符。我有一张带有字符串的打印纸页：“5XqaLB”
当我向相机的部分显示字符串以识别它时，我得到以下示例：

baseApi.setVariable("load_system_dawg", "0");
baseApi.setVariable("load_freq_dawg", "0");
baseApi.setVariable("load_punc_dawg", "0");
baseApi.setVariable("load_number_dawg", "0");
baseApi.setVariable("load_unambig_dawg", "0");
baseApi.setVariable("load_bigram_dawg", "0");
baseApi.setVariable("load_fixed_length_dawgs", "0");
baseApi.setVariable("segment_penalty_garbage", "0");
baseApi.setVariable("segment_penalty_dict_nonword", "0");
baseApi.setVariable("segment_penalty_dict_frequent_word", "0");
baseApi.setVariable("segment_penalty_dict_case_ok", "0");
baseApi.setVariable("segment_penalty_dict_case_bad", "0");

我认为这是因为tesseract试图用识别的字符猜测一个单词。我搜索了很多但找不到解决方案。任何人都有想法避免这种替代品吗？

已经尝试过白名单，黑名单和confs：

build.gradle

任何人都可以猜测如何让tesseract只识别普通字符吗？

Answer 1

我设法解决了我遇到的类似问题。在我的情况下，我正在识别板块字符。我没有在整个平板图像中使用tesseract，而是进行了分离字符的预处理，因此我可以分别对每个字符使用tesseract。我的配置varibles：

final TessBaseAPI baseApi = new TessBaseAPI();
    baseApi.init(TESSBASE_PATH, DEFAULT_DIC, TessBaseAPI.OEM_DEFAULT);
    baseApi.setDebug(true);
    baseApi.setVariable(TessBaseAPI.VAR_CHAR_WHITELIST, "ABCDEFGHIJKLMNOPQRSTUVXWYZ1234567890");

    baseApi.setPageSegMode(TessBaseAPI.PageSegMode.PSM_SINGLE_CHAR);
    baseApi.setVariable("load_system_dawg", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("load_freq_dawg", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("load_punc_dawg", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("load_number_dawg", TessBaseAPI.VAR_TRUE);
    baseApi.setVariable("load_unambig_dawg", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("load_bigram_dawg", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("load_fixed_length_dawgs", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("segment_penalty_garbage", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("segment_penalty_dict_nonword", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("segment_penalty_dict_frequent_word", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("segment_penalty_dict_case_ok", TessBaseAPI.VAR_FALSE);
    baseApi.setVariable("segment_penalty_dict_case_bad", TessBaseAPI.VAR_FALSE);
    return baseApi;

android tessaract API识别非单词

1 个答案: