我有一个像:
这样的元组mytuple = (10,10)
mylist = []
mylist.append(mytuple)
我想从mytuple中x的每次迭代中减去1,直到只有0,以便mylist看起来像
[(10,10),(9,10),(8,10),(7,10),etc.,(0,10)]
我在想一个for循环,但我无法弄清楚如何获得这个输出。感谢。
答案 0 :(得分:1)
mytuple = (10,10)
mylist = []
mylist.append(mytuple)
# store mytuple's first value
val = mytuple[0]
# while val is greater than 0
while (val > 0):
# subtract 1 from val
val -= 1
# generate tuple and add to list
mylist.append((val,10))
print(mylist)
答案 1 :(得分:1)
尝试类似:
mytuple = (10,10)
mylist = [(i,mytuple[1]) for i in range(mytuple[0],-1,-1)]
答案 2 :(得分:0)
范围允许您指定迭代所采取的步骤,这使您可以执行以下操作:
mytuple = (10,10)
mylist = []
for i in range(mytuple[0], -1, -1):
mylist.append((i, mytuple[1]))
print(mylist)
在此处查看此操作:http://ideone.com/wnM5zb