阅读长期运行的PHP进程客户端

时间:2015-12-07 13:14:24

标签: javascript php node.js socket.io ratchet

我想阅读一个长期运行的php进程,该进程将在满足条件时返回数据。

从我的研究中,我发现了:

  • 长轮询
  • 套接字(socket.io& node.js)
  • 棘轮

我正在努力理解&应用我的问题的实现。我在PHP中有以下循环:

public function store(ClientImpl $a)
{
    $request = \Illuminate\Support\Facades\Request::all();
    $originateMsg = new OriginateAction('Local/' . $request['agent'] . '@auto-answer');
    $originateMsg->setContext('G-Outgoing');
    $originateMsg->setPriority('1');
    $originateMsg->setExtension($request['dial']);
    $a->send($originateMsg);

    while(true) {
        if( $a->process() ) break;
        usleep(1000);
    }

    $a->close();

    echo 'OK';
    ob_end_flush();
    flush();
}

$a->process()调用以下方法:

/**
 * Main processing loop. Also called from send(), you should call this in
 * your own application in order to continue reading events and responses
 * from ami. 
 */
public function process()
{
    $msgs = $this->getMessages();
    foreach ($msgs as $aMsg) {
        if ($this->_logger->isDebugEnabled()) {
            $this->_logger->debug(
                '------ Received: ------ ' . "\n" . $aMsg . "\n\n"
            );
        }
        $resPos = strpos($aMsg, 'Response:');
        $evePos = strpos($aMsg, 'Event:');
        if (($resPos !== false) && (($resPos < $evePos) || $evePos === false)) {
            $response = $this->_messageToResponse($aMsg);
            $this->_incomingQueue[$response->getActionId()] = $response;
        } else if ($evePos !== false) {
            $event = $this->_messageToEvent($aMsg);
            $response = $this->findResponse($event);
            if ($response === false || $response->isComplete()) {
                $this->dispatch($event);
            } else {
                $response->addEvent($event);
            }
        } else {
            // broken ami.. sending a response with events without
            // Event and ActionId
            $bMsg = 'Event: ResponseEvent' . "\r\n";
            $bMsg .= 'ActionId: ' . $this->_lastActionId . "\r\n" . $aMsg;
            $event = $this->_messageToEvent($bMsg);
            $response = $this->findResponse($event);
            $response->addEvent($event);
        }
        if ($this->_logger->isDebugEnabled()) {
            $this->_logger->debug('----------------');
        }
    }
}

$a->process()然后堆叠事件消息,为了阅读这些消息,我创建了IEventListener的实现,在调用$a->process()时也称为“幕后”。

class VoipEventStart implements IEventListener
{
    public function handle(EventMessage $event)
    {
        $a = $event->getKeys();

        if( ($a['event'] == "Hangup" || $a['event'] == "HangupRequest") && strpos($a['channel'], 'SIP/') !== FALSE)
        {
            return true;
        }

        return false;
    }
}

当用户处于活动呼叫时,处理方法从Asterisk PBX系统读取事件。这意味着只要通话持续,过程循环就会持续。

如果浏览器没有加载/等待,我将如何执行此客户端?

1 个答案:

答案 0 :(得分:0)

您可以使用Server Sent Events或某些套接字实现,但最简单的可能是长轮询策略可以很好地运行。

为此,从客户端发送一个普通的AJAX请求,并使服务器仅在满足条件时返回。它可以像更改服务器端代码一样简单:

while(true) {
    if( $a->process() ) break;
    usleep(1000);
}
echo 'OK';
ob_end_flush();
flush();

客户端应该向启动上述循环的PHP文件发送一个简单的GET请求。这样,当响应返回到此请求时,您知道process()返回true。

客户端代码可能如下所示:

<div>Call status: <span id="status">In call</span></div>
<script>
  $.get('/check_call_status.php?callerId=123', function(response) {
    if(response === 'OK') {
      $('#staus').html('finished');
    }
  });
</script>

当然,处理超时可能会更复杂。例如。如果在给定时间段内对长轮询请求没有响应,请重新启动它 - 即中止请求并再次发送以避免客户端或服务器超时。