我有一个巨大的术语列表,我想从文本文件中提取并将它们分组到以下组之一:动物,艺术,建筑物,车辆,人,人,食物,玻璃,瓶子,标牌,口号,DJ,派对。我目前在tester2文件中有四个单词:
板 比萨 fearns 混合器
这是我的代码:
keyword_dictionary = {
'Animal' : ['animal', 'dog', 'cat'],
'Art' : ['art', 'sculpture', 'fearns'],
'Buildings' : ['building', 'architecture', 'gothic', 'skyscraper'],
'Vehicle' : ['car','formula','f-1','f1','f 1','f one','f-one','moped','mo ped','mo-ped','scooter'],
'Person' : ['person','dress','shirt','woman','man','attractive','adult','smiling','sleeveless','halter','spectacles','button','bodycon'],
'People' : ['people','women','men','attractive','adults','smiling','group','two','three','four','five','six','seven','eight','nine','ten','2','3','4','5','6','7','8','9','10'],
'Food' : ['food','plate','chicken','steak','pizza','pasta','meal','asian','beef','cake','candy','food pyramid','spaghetti','curry','lamb','sushi','meatballs','biscuit','apples','meat','mushroom','jelly', 'sorbet','nacho','burrito','taco','cheese'],
'Glass' : ['glass','drink','container','glasses','cup'],
'Bottle' : ['bottle','drink'],
'Signage' : ['sign','martini','ad','advert','card','bottles','logo','mat','chalkboard','blackboard'],
'Slogan' : ['Luck is overrated'],
'DJ' : ['dj','disc','jockey','mixer','instrument','turntable'],
'Party' : ['party']
}
y = 0
while (y < 1):
try:
def search(keywords, searchFor):
for item in keywords:
for terms in keywords[item]:
if searchFor in terms:
print item
with open("C:/Users/USERNAME/Desktop/tester2.txt") as termsdesk:
for line in termsdesk:
this = search (keyword_dictionary, line)
this2 = str(this)
#print this2
#print item
except KeyError:
break
y = y+1
我的结果应该是这样的:
Food
Food
Art
DJ
但我得到了这个:
DJ
我想象的是因为我的循环出了问题。有谁知道我需要改变什么?我试过移动&#34; while(y&lt; 1)&#34;但是我还没有能够得到我想要的结果。
答案 0 :(得分:2)
从搜索字词中删除前导/尾随空格。以下按预期工作:
def search(keywords, searchFor):
for key, words in keywords.iteritems():
if searchFor in words:
print key
with open("tester2.txt") as termsdesk:
for line in termsdesk:
this = search(keyword_dictionary, line.strip())
this2 = str(this)
$ cat tester2.txt
plate
pizza
fearns
mixer
$ python test4.py
Food
Food
Art
DJ
此外,如果您希望搜索词的数量相对于词典的大小较大,可以考虑性能改进:您可以从任何单词构建反向映射到其类别。例如,变换:
keyword_dict = {'DJ': ['mixer', 'speakers']}
进入
category_dict = {
'mixer': 'DJ',
'speakers':'DJ'
}
这种反向映射可以在开始时构建一次,然后在每个查询中重复使用,这样就可以将搜索功能转换为category_dict[term]
。这样查找速度会更快,分摊O(1)复杂度,并且更容易编写。
答案 1 :(得分:2)
以下方法更有意义:
keyword_dictionary = {
'Animal' : ['animal', 'dog', 'cat'],
'Art' : ['art', 'sculpture', 'fearns'],
'Buildings' : ['building', 'architecture', 'gothic', 'skyscraper'],
'Vehicle' : ['car','formula','f-1','f1','f 1','f one','f-one','moped','mo ped','mo-ped','scooter'],
'Person' : ['person','dress','shirt','woman','man','attractive','adult','smiling','sleeveless','halter','spectacles','button','bodycon'],
'People' : ['people','women','men','attractive','adults','smiling','group','two','three','four','five','six','seven','eight','nine','ten','2','3','4','5','6','7','8','9','10'],
'Food' : ['food','plate','chicken','steak','pizza','pasta','meal','asian','beef','cake','candy','food pyramid','spaghetti','curry','lamb','sushi','meatballs','biscuit','apples','meat','mushroom','jelly', 'sorbet','nacho','burrito','taco','cheese'],
'Glass' : ['glass','drink','container','glasses','cup'],
'Bottle' : ['bottle','drink'],
'Signage' : ['sign','martini','ad','advert','card','bottles','logo','mat','chalkboard','blackboard'],
'Slogan' : ['Luck is overrated'],
'DJ' : ['dj','disc','jockey','mixer','instrument','turntable'],
'Party' : ['party']
}
terms = {v2 : k for k, v in keyword_dictionary.items() for v2 in v}
with open('input.txt', 'r') as f_input:
for word in f_input:
print terms[word.strip()]
这首先是你现有的词典并反过来,以便更容易查找每个单词。
这将为您提供以下输出:
Food
Food
Art
DJ