Question

我使用d3强制定向图布局来显示一些数据。当我双击节点旁边的名称时，我想用新数据重新渲染图形。我找到了simular question on StackOverflow，但它并没有真正为我效劳。关键似乎是force.start();方法，我也称之为。{1}}方法。这是我到目前为止编码的内容。它缩短为绝对最小值。

var height =  600;
var width = 800;
var color = d3.scale.category20();
var svg = d3.select('body').append('svg').attr('width', width).attr('height',
        height).attr("pointer-events", "all").append("g").append("g");
svg.append("rect").attr("class", "overlay").attr("width", width).attr("height", height);

function draw(json) {
    var force = self.force = d3.layout.force()
        .nodes(json.nodes)
        .links(json.links)
        .gravity(.05)
        .distance(150)
        .charge(-100)
        .size([width, height])
        .start();

    var link = svg.selectAll(".link").data(json.links).enter().append("line")
            .attr("class", "link").style("stroke-width", 1);

    var gnodes = svg.selectAll('g.gnode').data(json.nodes).enter().append('g').classed('gnode', true);


    var node = gnodes.append("circle").attr("class", "node").attr("r", 5)
            .style("fill", function(d) {
                return color(d.group);
            });

    var labels = gnodes.append("text").text(function(d) {
        return d.name;
    }).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
        redraw();
    });
    gnodes.selectAll("circle.node").on("click", function() {
        d3.select(this);
    });
    force.on("tick", tick);

    function tick() {
      link.attr("x1", function(d) { return d.source.x; })
          .attr("y1", function(d) { return d.source.y; })
          .attr("x2", function(d) { return d.target.x; })
          .attr("y2", function(d) { return d.target.y; });
      gnodes.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
    }
force.start();
};


function invoke(){
    inputString = {
            "nodes":[
                     {"concept":"man","name":"John","id":0,"shortname":"","group":2},
                     {"concept":"woman","name":"Mia","id":1,"shortname":"","group":6},
                     {"concept":"child","name":"Harry","id":2,"shortname":"","group":7},
                     {"concept":"child","name":"Sally","id":3,"shortname":"","group":7},
                     {"concept":"old women","name":"Judith","id":4,"shortname":"","group":8},
                     {"concept":"old man","name":"Lionel","id":5,"shortname":"","group":7}
                  ],
                  "links":[
                     {"source":0,"target":1,"relation":"married"},
                     {"source":0,"target":2,"relation":"father"},
                     {"source":1,"target":2,"relation":"mother"},
                     {"source":0,"target":3,"relation":"father"},
                     {"source":1,"target":3,"relation":"mother"},
                     {"source":5,"target":2,"relation":"grandfather"},
                     {"source":5,"target":3,"relation":"grandfather"},
                     {"source":4,"target":2,"relation":"grandmother"},
                     {"source":4,"target":3,"relation":"grandmother"},
                     {"source":5,"target":1,"relation":"father"},
                     {"source":4,"target":1,"relation":"mother"}
                  ]
             };
    draw(inputString);
}

function redraw(){
    inputString = {
            "nodes":[
                     {"concept":"man","name":"Alan","id":0,"shortname":"","group":2},
                     {"concept":"woman","name":"Judith","id":1,"shortname":"","group":6},
                     {"concept":"child","name":"Jack","id":2,"shortname":"","group":7},
                     {"concept":"child","name":"Rosana","id":3,"shortname":"","group":7},
                     {"concept":"old women","name":"Evelyn","id":4,"shortname":"","group":8},
                     {"concept":"old man","name":"Charlie","id":5,"shortname":"","group":7}
                  ],
                  "links":[
                     {"source":0,"target":1,"relation":"married"},
                     {"source":0,"target":2,"relation":"father"},
                     {"source":1,"target":2,"relation":"mother"},
                     {"source":0,"target":3,"relation":"father"},
                     {"source":1,"target":3,"relation":"mother"},
                     {"source":5,"target":2,"relation":"grandfather"},
                     {"source":5,"target":3,"relation":"grandfather"},
                     {"source":4,"target":2,"relation":"grandmother"},
                     {"source":4,"target":3,"relation":"grandmother"},
                     {"source":5,"target":1,"relation":"father"},
                     {"source":4,"target":1,"relation":"mother"}
                  ]
             };
    draw(inputString);
}

var inputString = undefined;

invoke();

调用双击行为的部分在这里：

var labels = gnodes.append("text").text(function(d) {
        return d.name;
    }).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
        redraw();
});

redraw();有新数据，应该只调用我的函数再次绘制图形。对我来说，双击节点似乎只能工作一次。甚至他们也会绘制旧数据。我准备了一个fiddle demo，其中包含了迄今为止我所拥有的一切。
在重绘图表时我做错了什么？

Answer 1

在绘制函数中渲染之前，您需要删除节点和链接。

function draw(json) {
  svg.selectAll(".link").remove();//add this to remove the links
  svg.selectAll(".gnode").remove();//add this to remove the nodes
...your old code.

工作代码here。

重新渲染D3强制定向布局与新数据

1 个答案: