Question

我试图在屏幕上获取触摸的坐标，以显示弹出菜单

如何在页面视图控制器中使用

我在这里做错了什么？

function getAvengers() {
    return $http.get('https://maps.googleapis.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA')
        .then(getAvengersComplete)
        .catch(getAvengersFailed);

    function getAvengersComplete(response) {
        return response.data;
    }

    function getAvengersFailed(error) {
        console.log('XHR Failed for getAvengers.' + error.data);
    }
}
TestCtrl.dataTest = dataservice.getAvengers();
console.log(TestCtrl.dataTest.status);

Answer 1

在PageViewController中，如果你想弹出

在viewDidLoad中：

let tap = UITapGestureRecognizer(target: self, action: "showMoreActions:")
    tap.numberOfTapsRequired = 1
    view.addGestureRecognizer(tap)

让页面视图控制器继承UIGestureRecognizerDelegate，然后添加：

  func showMoreActions(touch: UITapGestureRecognizer) {

        let touchPoint = touch.locationInView(self.view)
        let DynamicView = UIView(frame: CGRectMake(touchPoint.x, touchPoint.y, 100, 100))
        DynamicView.backgroundColor=UIColor.greenColor()
        DynamicView.layer.cornerRadius=25
        DynamicView.layer.borderWidth=2
        self.view.addSubview(DynamicView)

}

UIPageViewController with TouchEvent

Answer 2

快捷键5：

override func viewDidLoad() {
    super.viewDidLoad()
    
    let tap = UITapGestureRecognizer(target: self, action: #selector(touchedScreen(touch:)))
    view.addGestureRecognizer(tap)
}

@objc func touchedScreen(touch: UITapGestureRecognizer) {
    let touchPoint = touch.location(in: self.view)
    print(touchPoint)
}

如何在iOS swift中获取分接点（坐标）

2 个答案: