Question

["name: edward, subjectId:1, remark:passed",
"name: edward, subjectId:3, remark:passed",
"name: Jamie, subject:1, remark:excellent"]

上面是一个混乱的输出，我无法控制。我必须将它映射并清理干净。理想的数组对象必须如下所示：

[{name:"edward",subjectId:1,3,remark:"passed},{name:"Jamie",subjectId:1,remark:"excellent"}]

但对我来说似乎不可能，因为它没有每条记录的唯一ID。我可以比较注释并正确分组subjectId，但是如果它在同一日期插入了一行呢？然后我的逻辑有缺陷。有什么想法吗？

Answer 1

尝试使用Array.prototype.map(); String.prototype.replace()与RegExp /(\w+)(?=:|,|$)/g ":"匹配后跟","，JSON.parse()或字符串结尾的字词，替换为带引号的字符串; var arr = ["name: edward, subjectId:1, remark:passed", "name: edward, subjectId:3, remark:passed", "name: Jamie, subject:1, remark:excellent" ]; var res = arr.map(function(val) { return JSON.parse("{" + val.replace(/(\w+)(?=:|,|$)/g, "\"$1\"") + "}") }); console.log(res); document.querySelector("pre").textContent = JSON.stringify(res, null, 2)

＆＃13;

<pre></pre>

＆＃13;

<input type="radio" name="position" id="left">
<input type="radio" name="position" id="center">
<input type="radio" name="position" id="right">

＆＃13;

Answer 2

你的输入非常接近JSON，你不得不抛弃字符串操作！

var input = [
    "name: edward, subjectId:1, remark:passed",
    "name: edward, subjectId:3, remark:passed",
    "name: Jamie, subject:1, remark:excellent"
];

function makeJson(str) { // Deal with each of your input strings
    function wrapKeyAndVal(str) { // Wrap the key and value pairs in double quotes
        var key = str.split(':')[0].trim();
        var val = str.split(':')[1].trim();
        return '"' + key + '"' + ':' + '"' + val + '"';
    }
    return str.split(',').map(wrapKeyAndVal).join(',');
}

input = input.map(makeJson);

// Parse each string into an object
var output = input.map(item => JSON.parse("{" + item + "}"))

// You'll end up with an array of objects
console.log(output);

将冗余对象值分组到数组对象中

2 个答案: