Question

我一直在做这个家庭作业一段时间我现在有2个问题远没有完成......这个问题尤其令我难以理解，我甚至不确定我明白它的要求......它已经晚了，咖啡已经消失了有人能指出我正确的方向......

**对于List letterGrades中的所有元素如果索引i处的元素等于grade，则将noOfGrades增加1。无论情况如何，都应该进行比较，即p / P / f / F.

这是我目前的代码列表......

/*
 * Calculate letter grades as P for Pass and F for Fail based on the marks obtained.
 * Find the number of instances with the given grades.
 */
namespace Ex1
{
    public partial class LetterGrade : Form
    {
        // Initialize string List
        public List<string> letterGrades = new List<string>();

        public LetterGrade()
        {
            InitializeComponent();
        }


        private void submitButton_Click(object sender, EventArgs e)
        {
            double marks = double.Parse(marksTextbox.Text); //Declare variable marks and set

            // If statements for marks
            if (marks>0 && marks<=60)
            {
                letterGrades.Add("F");
            }
            else if (marks>60 && marks<=100)
            {
                letterGrades.Add("P");
            }
            else
            {
                MessageBox.Show("Not a valid marks");
            }
            marksTextbox.Clear();
        }


        private void calculateButton_Click(object sender, EventArgs e)
        {
            string grade = letterGradeTextbox.Text; // initialize string grade
            int noOfGrades = 0;

            for (int i = 0; i < letterGrades.Count; i++)
            {
                if (grade == "P" || grade == "p") //Problem here, step 7a...could not initialize using [i]..tried using a workaround but it keeps total count..
                {
                    noOfGrades++;
                }
                else if (grade == "F" || grade == "f") 
                {
                    noOfGrades++;
                }
            }

            letterGradeTextbox.Clear();

            MessageBox.Show("Number of instances with given letter grade is: " + noOfGrades);
        }
    }
}

我很有可能过去想到月球和背部，但是如果有人可以指出我对了正确的兔子洞，那我就非常感激

Answer 1

试试这个

for (int i = 0; i < letterGrades.Count; i++)
{
    if (letterGrades[i].ToLower() == grade.ToLower())
    {
        noOfGrades++;
    }
}

基本上，对于letterGrades中的每个成绩，我们要检查该成绩是否等于grade }

C＃不知道从哪里开始

1 个答案: