Question

我有串行调度队列Q（另一个串行队列T作为目标），并且已经通过dispatch_async(Q, block)提交了几个块。有没有办法将待处理的块重新定位到另一个队列A？

我的简单测试表明，Q会尽快将阻止转发给T，因此设置新目标无效：

#define print(f, ...) printf(f "\n", ##__VA_ARGS__)

dispatch_queue_t Q = dispatch_queue_create("Q", DISPATCH_QUEUE_SERIAL);
dispatch_queue_t T = dispatch_queue_create("T", DISPATCH_QUEUE_SERIAL);
dispatch_queue_t A = dispatch_queue_create("A", DISPATCH_QUEUE_SERIAL);

dispatch_set_target_queue(Q, T);

dispatch_async(T, ^{ print("T sleeping"); sleep(2); print("T ready"); });
dispatch_async(A, ^{ print("A sleeping"); sleep(5); print("A ready"); });

dispatch_async(Q, ^{
    print("block 1");
    dispatch_set_target_queue(Q, A); // no effect!
});
dispatch_async(Q, ^{ print("block 2"); });
dispatch_async(Q, ^{ print("block 3"); });
dispatch_async(Q, ^{ print("block 4"); });

输出：

A sleeping
T sleeping
(wait 2 seconds)
T ready
block 1
block 2
block 3
block 4
(wait 3 seconds)
A ready

如您所见，即使手动状态：

，块2-4仍被固定到T

新的目标队列设置将在对象的块执行之间生效，但不会在任何现有块执行的中间生效（非抢先）。

我不清楚这是否仅适用于派遣来源，或者现有的＆＃34;意味着已提交（甚至尚未执行）的块，但无论如何，我的串行队列不会发生任何事情。

有办法吗？

Answer 1

好的，经过研究，我想出了以下解决方案。它基于自定义调度源，我认为这是及时提交块的唯一方法。

BlockSource.h：

dispatch_source_t dispatch_block_source_create(dispatch_queue_t queue);
void dispatch_block_source_add_block(dispatch_source_t source, dispatch_block_t block);

BlockSource.c：

struct context {
    CFMutableArrayRef array;
    pthread_mutex_t mutex;
    dispatch_source_t source;
};

static void
s_event(struct context *context)
{
    dispatch_block_t block;
    CFIndex pending;

    pthread_mutex_lock(&context->mutex); {
        block = CFArrayGetValueAtIndex(context->array, 0);
        CFArrayRemoveValueAtIndex(context->array, 0);
        pending = CFArrayGetCount(context->array);
    }
    pthread_mutex_unlock(&context->mutex);

    block();
    Block_release(block);

    if (pending)
        dispatch_source_merge_data(context->source, 1);
}

static void
s_cancel(struct context *context)
{
    CFIndex count = CFArrayGetCount(context->array);
    for (CFIndex i = 0; i < count; i++) {
        dispatch_block_t block = CFArrayGetValueAtIndex(context->array, i);
        Block_release(block);
    }
    CFRelease(context->array);
    pthread_mutex_destroy(&context->mutex);
    print("canceled");
}

dispatch_source_t
dispatch_block_source_create(dispatch_queue_t queue)
{
    dispatch_source_t source = dispatch_source_create(DISPATCH_SOURCE_TYPE_DATA_OR, 0, 0, queue);

    struct context *context = calloc(1, sizeof(*context));
    context->array = CFArrayCreateMutable(kCFAllocatorDefault, 0, NULL);
    pthread_mutex_init(&context->mutex, NULL);
    context->source = source;

    dispatch_set_context(source, context);
    dispatch_source_set_event_handler_f(source, (dispatch_function_t)s_event);
    dispatch_source_set_cancel_handler_f(source, (dispatch_function_t)s_cancel);
    dispatch_set_finalizer_f(source, (dispatch_function_t)free);

    return source;
}

void
dispatch_block_source_add_block(dispatch_source_t source, dispatch_block_t block)
{
    struct context *context = dispatch_get_context(source);

    pthread_mutex_lock(&context->mutex); {
        CFArrayAppendValue(context->array, Block_copy(block));
        dispatch_source_merge_data(context->source, 1);
    }
    pthread_mutex_unlock(&context->mutex);
}

测试用例：

dispatch_queue_t T = dispatch_queue_create("T", DISPATCH_QUEUE_SERIAL);
dispatch_queue_t A = dispatch_queue_create("A", DISPATCH_QUEUE_SERIAL);

static int queue_name_key;
dispatch_queue_set_specific(T, &queue_name_key, "T", NULL);
dispatch_queue_set_specific(A, &queue_name_key, "A", NULL);

dispatch_source_t source = dispatch_block_source_create(T);
dispatch_resume(source);

for (int i = 1; i <= 10; i++) {
    dispatch_block_source_add_block(source, ^{
        print("block %d on queue %s", i, dispatch_get_specific(&queue_name_key));
        sleep(1);

        if (i == 2) {
            dispatch_set_target_queue(source, A);
        }
        else if (i == 5) {
            dispatch_source_cancel(source);
            dispatch_release(source);
        }
    });
}

输出：

block 1 on queue T
block 2 on queue T
block 3 on queue A
block 4 on queue A
block 5 on queue A
canceled

至少现在它遵循调用dispatch_set_target_queue()之后的调度源方案。这意味着如果在一个提交的块内部设置了新的目标队列，则可以保证所有剩余的块将进入新队列。

可能仍然包含错误。

重定向块提交到调度队列

1 个答案: