Question

我遇到运行Client.py时出现额外GUI的问题。我想这是因为我在Menu.py的第9行设置了myMenu = Toplevel()，但如果我不在那里，那么在第10行之前，第10行会抛出错误（并且菜单GUI永远不会弹出因为它）：

Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Pat\AppData\Local\Programs\Python\Python35-32\lib\tkinter\__init__.py", line 1549, in __call__
    return self.func(*args)
  File "C:\Users\Pat\Documents\GitHub\DunderMifflinSales\DunderMifflinClient.py", line 48, in _login_btn_clicked
    Menu.create_menu()
  File "C:\Users\Pat\Documents\GitHub\DunderMifflinSales\Menu.py", line 53, in create_menu
    mf = MenuFrame(root)
  File "C:\Users\Pat\Documents\GitHub\DunderMifflinSales\Menu.py", line 11, in __init__
    mainframe = ttk.Frame(myMenu,padding="3 3 12 12")
NameError: name 'myMenu' is not defined

我是python和Tkinter的新手，想要解释一下我做错了什么以及我能做些什么来解决它。谢谢！

Client.py：

import socket
from tkinter import *
import tkinter.messagebox as tm
from tkinter import ttk
import Menu

serverName = 'localhost'
serverPort = 12000
clientSocket = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)


class LoginFrame(Frame):

    def __init__(self, master):
        super().__init__(master)

        self.label_1 = Label(self, text="Username")
        self.label_2 = Label(self, text="Password")

        self.entry_1 = Entry(self)
        self.entry_2 = Entry(self, show="*")

        self.label_1.grid(row=0, sticky=E)
        self.label_2.grid(row=1, sticky=E)
        self.entry_1.grid(row=0, column=1)
        self.entry_2.grid(row=1, column=1)

        self.logbtn = Button(self, text="Login", command = self._login_btn_clicked)
        self.logbtn.grid(columnspan=2)

        self.pack()


    def _login_btn_clicked(self):

        username = self.entry_1.get()
        clientSocket.sendto(username.encode('UTF-8'),(serverName, serverPort))

        password = self.entry_2.get()
        clientSocket.sendto(password.encode('UTF-8'),(serverName, serverPort))

        message, address = clientSocket.recvfrom(1024)
        message = message.decode('UTF-8')

        if message == "200 OK":
            Menu.create_menu()

        else:
            tm.showinfo("Login error", message)


def main():
    root = Tk()
    root.title("Dunder Mifflin GUI")
    root.geometry('{}x{}'.format(270, 80))
    lf = LoginFrame(root)
    root.mainloop()

if __name__ == "__main__":
    main()

Menu.py：

from tkinter import *
from tkinter import ttk

class MenuFrame(Frame):

    def __init__(self, master):
        super().__init__(master)

        myMenu = Toplevel()

        mainframe = ttk.Frame(myMenu,padding="3 3 12 12")
        mainframe.grid(column = 0, row = 0, sticky = (N, W, E, S))
        mainframe.columnconfigure(0, weight = 1)
        mainframe.rowconfigure(0, weight = 1)

        name = "John"
        sales = StringVar()
        moreSales = StringVar()
        sales.set("1")

        welcome = "Welcome, " + name + "!"

        sales_entry = ttk.Entry(mainframe, width = 7, textvariable = moreSales)

        ttk.Label(mainframe, text = welcome).grid(column = 2, row = 1, sticky = W)

        ttk.Label(mainframe, text = "Current Sales:").grid(column = 1, row = 2, sticky = W)
        ttk.Label(mainframe, textvariable = sales).grid(column = 2, row = 2, sticky = (E))
        ttk.Label(mainframe, text = "sales").grid(column = 3, row = 2, sticky = W)

        ttk.Label(mainframe, text = "Add Sales").grid(column = 1, row = 3, sticky = W)
        sales_entry.grid(column = 2, row = 3, sticky = (W, E))
        ttk.Button(mainframe, text = "Add", command = MenuFrame.add(sales, moreSales)).grid(column = 3, row = 3, sticky = W)

        ttk.Button(mainframe, text = "Log Out", command = MenuFrame.logout).grid(column = 2, row = 4, sticky = W)


    def add(sales, moreSales):

        try:
            value1 = int(sales.get())
            value2 = int(moreSales.get())
            sales.set(value1 + value2)
        except ValueError:
            pass

    def logout():
        myMenu.destroy()

def create_menu():
    root = Tk()
    root.title("Dunder Mifflin GUI")
    mf = MenuFrame(root)
    root.mainloop()
    root.destroy()


if __name__ == "__create_menu__":
    create_menu()

Answer 1

您问题中的堆栈跟踪似乎与您问题中的代码无关，因为堆栈跟踪显示代码mf = Menu.MenuFrame(mymenu)，但该代码在您发布的代码中不存在。

您的代码正在创建一个“额外的GUI”，因为您正在告诉它。您只能创建Tk的单个实例，但您要创建两个。{1}}。您可以在Client.py（方法main）中创建一个，在Menu.py中创建一个（方法create_menu）。

通常应用于Tk实例的名称是root，因为这是（并且必须是）窗口小部件层次结构的根。你不能在树上有两个根。

与手头的问题无关，您是否知道if __name__ == "__create_menu__"始终是False？

Tkinter发射额外的空GUI

1 个答案: