Question

我希望在Youtube搜索中提取第一个链接的网址，而无需加载视频页面。

import urllib
from selenium import webdriver
song='burning bridges'
songsearch=urllib.parse.quote_plus(song)
driver = webdriver.Chrome()
driver.get('https://www.youtube.com/results?search_query=%s+lyrics' % songsearch)
urlinc = driver.find_element_by_partial_link_text(song)

print (urlinc)
print ('done')
driver.quit()

HREF =＃＆34; /观看V = R8tVZ_QfYe4＆＃34？; class =＆＃34; yt-uix-sessionlink yt-uix-tile-link yt-ui-ellipsis yt-ui-ellipsis-2 spf-link＆＃34;数据sessionlink =＆＃34; itct = CB0Q3DAYACITCLqBt - IyMkCFVPRvgodYRkCZij0JFIWYnVybmluZyBicmlkZ2VzIGx5cmljcw＆＃34; title =＆＃34; OneRepublic-Burning Bridges（歌词）HD NATIVE＆＃34;的rel =＆＃34; SPF-预取＆＃34;咏叹调-describedby =＆＃34;描述-ID-231739＆＃34; dir =＆＃34; ltr＆＃34;＆gt; OneRepublic-Burning Bridges（歌词）HD NATIVE

输出：

selenium.webdriver.remote.webelement.WebElement (session="9bf01a91206f82d9462b6803c5084aa5", element="0.22866418561898172-1")

done

Answer 1

你可以尝试：

>>> urlinc.get_attribute('href')
'https://www.youtube.com/watch?v=omhYPjksUy8'
>>>

如何使用selenium提取元素（href）并保存到变量中

1 个答案: