Question

我正在使用3个PickerViews并且一些字很大而且不适合PickerView并且看起来像这样＆＃34; IamAWordVer ...＆＃34;而且我不希望这种情况发生。我希望它调整字体大小或类似于适合PickerView中的所有单词，但我不会影响PickerView的大小或其他选择器视图的字体大小，包括此PickerView中发生的单词。

例如，所有单词都使用默认值，如果不适合调整大小以适合所有单词。

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()

    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = oneText[row] as? NSAttributedString
    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = twoText[row] as? NSAttributedString
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.attributedText = threeText[row] as? NSAttributedString
    }
    return pickerLabel
}

它显示所有空白

Answer 1

在其上使用nameOfLabel.adjustsFontSizeToFitWidth = true。

Answer 2

我这样解决了：

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()


    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = oneText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle

    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = twoText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        let titleData = threeText[row]
        let myTitle = NSAttributedString(string: titleData as! String, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 20.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
        pickerLabel.attributedText = myTitle
    }
    return pickerLabel
}

Answer 3

您正在将一个String转换为NSAttributedString。

尝试：

func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView?) -> UIView {
    let pickerLabel = UILabel()

    if pickerView == pvOne{
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = oneText[row]
    }
    else if(pickerView == pvTwo){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = twoText[row]
    }
    else if(pickerView == pvThree){
        pickerLabel.adjustsFontSizeToFitWidth = true
        pickerLabel.text = threeText[row]
    }
    return pickerLabel
}

如何在UIPickerView中调整文本大小而不显示...？

3 个答案: