Question

urls.py

urlpatterns = [
url(r'^$', views.gallery, name='home'),
url(r'^(?P<album_id>\d+)/(?P<pic_id>\d+)/$', views.details, name='details'),
url(r'^(?P<album_id>\d+)/', views.album_details, name='album_details'),
]

views.py

def details(request, pic_id):

picture = get_object_or_404(Picture, pk=pic_id)
print("accessed details %s" %picture)

context = {
    "picture": picture
}

return render(request, "picture_details.html", context)

gallery_details.html

{% for picture in pictures %}
        <div class="img">
            <a href="{% url 'gallery:details' picture.id %}">
                <img src="{{ picture.picture_thumbnail.url }}" />
            </a>
            <div class="desc">{{ picture.description|truncatewords:5 }}</div>
        </div>
    {% endfor %}

当我尝试运行时，我得到一个异常值：

Reverse for 'details' with arguments '(3,)' and keyword arguments '{}' not found. 1 pattern(s) tried: ['gallery/(?P<album_id>\\d+)/(?P<pic_id>\\d+)/$']

它应该加载单个图像的页面，但它不会。不知道为什么。

Answer 1

您可能需要重新排列网址，以便首先使用不太具体的网址

url(r'^(?P<album_id>\d+)$', views.album_details, name='album_details'),
url(r'^(?P<album_id>\d+)/(?P<pic_id>\d+)/$', views.details, name='details'),

您还会注意到我修改了第一个正则表达式以包含$字符以表示匹配结束

多个django网址参数不起作用

1 个答案: