Question

到目前为止，我已经成功删除了第i个索引中的所有内容，但是我需要能够在第i个索引之后将节点从第i个索引之后连接到节点，这是我到目前为止所做的。

LinklistNode* remove_node(LinklistNode* list_head, int index){
if(list_head != NULL){
    LinklistNode* temp;
    if(list_head-> next ==NULL){
        temp = list_head;
        list_head = NULL;
    }
    else{
        LinklistNode* list_pointer = list_head;
        LinklistNode* next_list_pointer = list_pointer->next;
        while(next_list_pointer->next != NULL && index > 0){
            index--;
            list_pointer = next_list_pointer;
            next_list_pointer = next_list_pointer->next;
        }
        temp = next_list_pointer;
        list_pointer->next = NULL;
    }
    free(temp);
   }
   return list_head;
}

Answer 1

要链接索引前后的节点，请将list_pointer->next指向next_list_pointer->next

while(next_list_pointer->next != NULL){
        index--;
        if (index == 0) break;
        list_pointer = next_list_pointer;
        next_list_pointer = next_list_pointer->next;
}
temp = next_list_pointer;
list_pointer->next = temp->next;

Answer 2

为了在第i个元素之前连接节点，请使用list_pointer。有类似的东西 ...

using System;
using System.Windows.Forms;

namespace Project6
{
class Student
{
    //Initialize variables
    private string[] studentInformationArray;

    //Constructor that accepts the studentInformationArray as an argument
    public Student(string[] studentInformationArray)
    {
        this.studentInformationArray = studentInformationArray;
    }

    public Student()
    {
        string className = studentInformationArray[1];
        string semester = studentInformationArray[2];
        string picture = studentInformationArray[3];
        int project1 = Convert.ToInt32(studentInformationArray[4]);
        int project2 = Convert.ToInt32(studentInformationArray[5]);
        int project3 = Convert.ToInt32(studentInformationArray[6]);
        int project4 = Convert.ToInt32(studentInformationArray[7]);
        int project5 = Convert.ToInt32(studentInformationArray[8]);
        int project6 = Convert.ToInt32(studentInformationArray[9]);
        int midtermExam = Convert.ToInt32(studentInformationArray[10]);
        int finalExam = Convert.ToInt32(studentInformationArray[11]);
    }

    public string GetName()
    {
        string studentName;
        studentName = studentInformationArray[0];
        return studentName;
    }

}


}

... 这应该几乎涵盖删除部分，只需确保包含您的基本案例。

Answer 3

使用指针指向节点的指针的替代方法：

LinklistNode* remove_node(LinklistNode* list_head, int index)
{
LinklistNode **ppNode = &list_head;
    if(list_head == NULL)
        return NULL;
    while(index--){
        ppNode = &((*ppNode)->next);
        if(*ppNode == NULL)             /* if index not in list */
            return list_head;           /*   just return */
    }
    *ppNode = (*ppNode)->next;          /* delete node */
    return list_head;
}

根据您的at索引从C中的链表中删除

3 个答案: