Question

我有一个由echo显示的表单，我试图在提交后刷新页面，以便当输入无效详细信息时，可以将登录尝试添加到计数中，显示表单但是页面不会再刷新以添加算一算，这就是我所拥有的：

  $pdo = new PDO($dsn, $username, $password, $options);

  $max_time_in_seconds = 10;

  $max_attempts = 3;




if(login_attempt_count($max_time_in_seconds, $pdo) <= $max_attempts) {

    $form = "<form name='login' class='profile' id='form_id' action=''   
    method='post' accept-charset='utf-8'>
    <fieldset>
            <legend>Login</legend>
            <label for='username'>User name</label>
            <input type='text' name='username' id='username' autofocus  
            placeholder='User name MAX 10'  maxlength='10' title='You can 
            use characters & numbers' required />
            <label for='password'>Password</label>
            <input type='password' id='password' name='password'  
             />
             <br>
            <input type='submit' class='btn' value='Login' id='submit'   
             onSubmit='window.parent.location.reload();' />

           </form>";  
} else {

   $msg2 = " You have been BLOCKED try again in 10 minutes";



}

如果我刷新页面三次被阻止，这就是我想要输入三次提交的内容我试过添加

       <?php echo htmlspecialchars($_SERVER['PHP_SELF']);?>

我只是空白的白屏......

         if($_SESSION['user'] { header("location: memberlist.php");  }
         else
         if($_SESSION['user']['blacklisted_users'] == 'blocked') {       
         header("location: blocked.php");}
         else



        header("Location: private.php");
        die("Redirecting to: private.php");
         }

        else
         {

        $msg = " Username or Password INCORRECT";

          }

我认为最后的其他方法是阻止页面刷新，因为它只是回显错误

登录检查：

      $query = "
        SELECT
            id,
            username,
            password,
            salt,
            email,
            firstname,
            surname,
            address,
            town,
            postcode,
            type,
            blacklisted_users
        FROM users
        WHERE
            username = :username
    ";


    $query_params = array(
        ':username' => $_POST['username']);


    try
    {
        $stmt = $db->prepare($query);
        $result = $stmt->execute($query_params);

    }
    catch(PDOException $ex)
    {

        die("Failed to run query: " . $ex->getMessage());
    }


    $login_ok = false;


    $row = $stmt->fetch();
    if($row)
    {

然后进行密码检查......

Answer 1

您忘记关闭Replace标记了。在结束表单标记<fieldset>之前添加</fieldset>。

编辑：
你的中有些错误您应该在</form>之后添加exit(); 此外，header();只是一个变量，将其更改为$_SESSION['user']，因为我认为这就是您要做的事情

你也错过了一些isset($_SESSION['user'])

{}

提交后回显表单并在同一页面上重新加载

1 个答案: