Question

我有问题。请查看我的main.php和upload.php

main.php

<?php
include "include/db_connection.php";
$id     = isset($_GET['id']) ? $_GET['id'] : "";

if ($id=="") {
        echo "<script>alert('Pilih Mahasiswa yang Ingin Unggah Berkas!');</script>";
        echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>";
    } else {
        $query = mysql_query("SELECT mahasiswa.nim, mahasiswa.nama, mahasiswa.jurusan 
                              FROM mahasiswa 
                              WHERE mahasiswa.nim = '$id'");
        while ($hisal=mysql_fetch_array($query)){
                    $nim    = $hisal['nim'];
                    $nama   = $hisal['nama'];
                    $jur    = $hisal['jurusan'];
                }   
            }
?>
<table>
    <tr>
        <td>NIM</td>
        <td>:</td>
        <td><?php echo $nim;?></td>
    </tr>
    <tr>
        <td>Nama</td>
        <td>:</td>
        <td><?php echo $nama;?></td>
    </tr>
    <tr>
        <td>Jurusan</td>
        <td>:</td>
        <td><?php echo $jur;?></td>
    </tr>
</table><br><br>


<form enctype="multipart/form-data" method="POST" action="?page=upload">
    <table border="1" width="50%">
        <tr>
            <td align="center">Jenis Berkas</td>
            <td align="center">Berkas</td>
            <td align="center">Aksi</td>
        </tr>
        <tr>
            <td align="center">Foto</td>
            <td align="center"><input type="file" name="foto" accept="image/jpeg"></td>
            <td align="center"><?php echo"<a href='?page=prosesUbah2&id=$hisal[nim];'>Ubah</a> | 
                           <a href='?page=prosesHapus2&id=$id' onclick='return confirm(\"Anda yakin ingin menghapus berkas dari nim $id ?\")'>Hapus</a>"
                ?>
            </td>
        </tr>
        <tr>
            <td align="center">Scan KTM</td>
            <td align="center"><input type="file" name="ktm" accept="image/jpeg"></td>
            <td align="center"><?php echo"<a href='?page=prosesUbah2&id=$id'>Ubah</a> | 
                           <a href='?page=prosesHapus2&id=$id' onclick='return confirm(\"Anda yakin ingin menghapus berkas dari nim $id ?\")'>Hapus</a>"
                ?>
            </td>
        </tr>
        <tr>

            <td colspan="3" align="center"><input type="submit" name="Unggah" id="Unggah" value="Unggah Berkas"></td>

        </tr>
    </table>
</form>

upload.php的

<?php
include "include/db_connection.php";
$id     = isset($_GET['id']) ? $_GET['id'] : "";
$file       = "uploads/".$_FILES["foto"]["name"];

if ($_FILES["foto"]["error"] > 0 && $id==""){
    echo "<script>alert('Upload Failed')</script>";
    echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>";
    } else {
        move_uploaded_file($_FILES["foto"]["tmp_name"], "uploads/".$_FILES["foto"]["name"]);
        $sql=mysql_query("INSERT INTO mahasiswa VALUE ('','','','','','','$file','','') WHERE mahasiswa.nim='$id'");

        if ($sql){
            echo "<script>alert('Upload Gambar Sukses')</script>";
            echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>";
            } else{
                echo "<script>alert('Upload Failed')</script>";
                echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>";
                }
        }

?>

将图像文件复制到uploads文件夹，但其路径不存储在数据库中。当我点击“Unggah Berkas”按钮时，警报显示“上传失败”，但图像被复制到上传文件夹。你能帮助我吗？不管怎样，谢谢。

更新

我已经改变了这个

<form enctype="multipart/form-data" method="POST" action="?page=upload&id=<?php echo $id; ?>">

     //my code

</form>

和这个

    <?php
    include "include/db_connection.php";
    $id         = isset($_GET['id']) ? $_GET['id'] : "";
    $file       = "uploads/".$_FILES["foto"]["name"];

    if ($_FILES["foto"]["error"] > 0 || $id==""){
        echo "<script>alert('Upload Failed')</script>";
        echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>";
        } else {
            move_uploaded_file($_FILES["foto"]["tmp_name"], "uploads/".$_FILES["foto"]["name"]);
            $sql=mysql_query("INSERT INTO mahasiswa VALUE ('','','','','','','$file','','') WHERE mahasiswa.nim='$id'");    
            } 
?>

仍未存入数据库

Answer 1

路径无法存储在表格中，因为您未在网址中发送id。您的<form>标记应如下所示：

<form enctype="multipart/form-data" method="POST" action="upload.php?id=<?php echo $id; ?>">

    // your code

</form>

<强>更新

并且还会像这样更改if条件：

if($_FILES["foto"]["error"] > 0 || $id==""){

    // error

}else {

    // no error

}

<强>重新编辑：

这将是您的目录结构：

include
    |--db_connection.php
uploadform
    |--main.php
    |--upload.php
uploads

的 main.php

假设用户的ID为12，那么您必须像这样调用main.php， main.php？id = 12

<?php require_once("../include/db_connection.php"); $id = isset($_GET['id']) ? $_GET['id'] : ""; if ($id=="") { echo "<script>alert('Pilih Mahasiswa yang Ingin Unggah Berkas!');</script>"; echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>"; } else { $query = mysql_query("SELECT mahasiswa.nim, mahasiswa.nama, mahasiswa.jurusan FROM mahasiswa WHERE mahasiswa.nim = '$id'"); while ($hisal=mysql_fetch_array($query)){ $nim = $hisal['nim']; $nama = $hisal['nama']; $jur = $hisal['jurusan']; } } ?> <table> <tr> <td>NIM</td> <td>:</td> <td><?php echo $nim;?></td> </tr> <tr> <td>Nama</td> <td>:</td> <td><?php echo $nama;?></td> </tr> <tr> <td>Jurusan</td> <td>:</td> <td><?php echo $jur;?></td> </tr> </table><br><br> <form enctype="multipart/form-data" method="POST" action="upload.php?id=<?php echo $id; ?>"> <table border="1" width="50%"> <tr> <td align="center">Jenis Berkas</td> <td align="center">Berkas</td> <td align="center">Aksi</td> </tr> <tr> <td align="center">Foto</td> <td align="center"><input type="file" name="foto" accept="image/jpeg"></td> <td align="center"><?php echo"<a href='?page=prosesUbah2&id=$hisal[nim];'>Ubah</a> | <a href='?page=prosesHapus2&id=$id' onclick='return confirm(\"Anda yakin ingin menghapus berkas dari nim $id ?\")'>Hapus</a>" ?> </td> </tr> <tr> <td align="center">Scan KTM</td> <td align="center"><input type="file" name="ktm" accept="image/jpeg"></td> <td align="center"><?php echo"<a href='?page=prosesUbah2&id=$id'>Ubah</a> | <a href='?page=prosesHapus2&id=$id' onclick='return confirm(\"Anda yakin ingin menghapus berkas dari nim $id ?\")'>Hapus</a>" ?> </td> </tr> <tr> <td colspan="3" align="center"><input type="submit" name="Unggah" id="Unggah" value="Unggah Berkas"></td> </tr> </table> </form>

的 upload.php的

<?php require_once("../include/db_connection.php"); $id = isset($_GET['id']) ? $_GET['id'] : ""; $file = "uploads/".$_FILES["foto"]["name"]; if ($_FILES["foto"]["error"] > 0 || $id==""){ echo "<script>alert('Upload Failed')</script>"; echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>"; } else { move_uploaded_file($_FILES["foto"]["tmp_name"], "../uploads/".$_FILES["foto"]["name"]); $sql=mysql_query("INSERT INTO mahasiswa VALUE ('','','','','','','$file','','') WHERE mahasiswa.nim='$id'"); if ($sql){ echo "<script>alert('Upload Gambar Sukses')</script>"; echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>"; } else{ echo "<script>alert('Upload Failed')</script>"; echo "<meta http-equiv='refresh' content='0; url=?page=tugas2'>"; } } ?>

Answer 2

只需从

更改查询

$sql=mysql_query("INSERT INTO mahasiswa VALUE ('','','','','','','$file','','') WHERE mahasiswa.nim='$id'");

到

$sql=mysql_query("UPDATE mahasiswa SET foto='$foto' WHERE mahasiswa.nim='$id'");

PHP：获取图像路径并存储到数据库

2 个答案: