Question

如何使用包含它的'status'='start'来获取以获得结尾的id开头的一组kol_name。这意味着，我从外部得到'id'并希望从'start'包含一组列到没有他的下一个'start'，或者最后'add'，结果用于动态SQL

id      kol_name      status
------------------------------
44     kol_name_1      add
43     kol_name_2      add
42     kol_name_3      add  
41     kol_name_4     start 
40     kol_name_5      add
39     kol_name_6     start 
37     kol_name_7     start

我的预期输出是当我得到id 44

kol_name
--------------------
kol_name_1      
kol_name_2      
kol_name_3       
kol_name_4

我的预期输出是当我得到你的身份37

kol_name
--------------------   
kol_name_7

我的预期输出是当我得到id 39

kol_name
--------------------   
kol_name_5 
kol_name_6

我该怎么做？

Answer 1

嗯。一种方法是计算第一个开始“在”给定的id之后（“之后”似乎是一个较小的id，这就是为什么我把它放在引号中）。然后，您可以使用简单的逻辑：

select t.*
from t cross join
     (select max(id) as startid
      from t
      where id <= 44 and status = 'start'
     ) tt
where t.id <= 44 and t.id >= tt.startid;

如果您只想在查询中提及“44”：

select t.*
from t cross join
     (select theid, max(id) as startid
      from t cross join (select 44 as theid from dual)
      where id <= theid and status = 'start'
     ) tt
where t.id <= tt.theid and t.id >= tt.startid;

编辑：

此代码仅返回一行：

with t as (
    select 44 as id, 'kol_name_1' as kol_name, 'add' as status from dual union all
    select 43, 'kol_name_2', 'add' from dual union all
    select 42, 'kol_name_3', 'add' from dual union all
    select 41, 'kol_name_4', 'start' from dual union all
    select 40, 'kol_name_5', 'add' from dual union all
    select 39, 'kol_name_6', 'start' from dual union all
    select 37, 'kol_name_7', 'start' from dual 
   )
select t.*
from t cross join
     (select max(id) as startid
      from t
      where id <= 39 and status = 'start'
     ) tt
where t.id <= 39 and t.id >= tt.startid;

Here是一个SQL小提琴

编辑II;

哦，你想要带有39的两个行。如果是这种情况，请使用no equality更改startid的定义：

select t.*
from t cross join
     (select max(id) as startid
      from t
      where id < 44 and status = 'start'
     ) tt
where t.id <= 44 and t.id >= tt.startid;

如何从指定的id开始组

1 个答案: