Question

我在Android上部署了我的应用程序。

我在我的主Activity按钮中放了一个，当你点击时，你必须显示一个对话框，我在2 EditText上写文字并按下OK按钮。

我的问题是......如何在主Activity的事件中获取EditText的值？

onDialogPositiveClick(...)
onDialogNegativeClick(...)

这是我的对话 DialogAlex.java

的课程

public class DialogAlex extends DialogFragment {

    public interface NoticeDialogListener {
        public void onDialogPositiveClick(DialogFragment dialog,int id);
        public void onDialogNegativeClick(DialogFragment dialog,int id);
    }
    NoticeDialogListener mListener;

    @Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);        
        try {     
            mListener = (NoticeDialogListener) activity;
        } catch (ClassCastException e) {
            // The activity doesn't implement the interface, throw exception
            throw new ClassCastException(activity.toString()
                    + " must implement NoticeDialogListener");
        }
    }

    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {     
        AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());

        LayoutInflater inflater = getActivity().getLayoutInflater();
        builder.setView(inflater.inflate(R.layout.dialog_signin, null)) //This layout contains only two EditText, ET1 and ET2.

                .setPositiveButton("adicionar", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {

                        mListener.onDialogPositiveClick(DialogAlex.this,id);
                    }
                })
                .setNegativeButton("cancelar", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {

                        mListener.onDialogNegativeClick(DialogAlex.this, id);
                    }
                });
        return builder.create();
    }
}

这是我的活动主页。

...
@Override
    public boolean onOptionsItemSelected(MenuItem item) {       
        int id = item.getItemId();

        //noinspection SimplifiableIfStatement
        if (id == R.id.action_settings) {
            return true;
        }
        if (id == R.id.telefono)
        {
            showNoticeDialog();  //call dialog        
            return true;
        }

        return super.onOptionsItemSelected(item);
    }

    public void showNoticeDialog() {        
        DialogFragment dialog = new DialogAlex();
        dialog.show(getSupportFragmentManager(), "NoticeDialogFragment");
    }

    @Override
    public void onDialogPositiveClick(DialogFragment dialog,int id) {        
        //**************HOW obtaining values EditText?*****************************
        Toast.makeText(this,"hola", Toast.LENGTH_LONG).show();      
    }

    @Override
    public void onDialogNegativeClick(DialogFragment dialog,int id) {

    }
...

问候

Answer 1

您可以将其添加到界面的方法中。 E.g。

public interface NoticeDialogListener {
    public void onDialogPositiveClick(DialogFragment dialog, String value, int id);
    public void onDialogNegativeClick(DialogFragment dialog,int id);
}

然后

onCreateDialog

@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {     
    AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());

    LayoutInflater inflater = getActivity().getLayoutInflater();
    final View view = inflater.inflate(R.layout.dialog_signin, null);
    builder.setView(view)  .setPositiveButton("adicionar", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id) {
                   EditText edittext = (EditText) view.findViewById(R.id.editText)
                    mListener.onDialogPositiveClick(DialogAlex.this, edittext.getText().toString(), id);
                }
            })

Answer 2

你真的很接近，你必须通过你的听众传递这些价值。

将您的界面更改为：

public interface NoticeDialogListener {
    public void onDialogPositiveClick(String input1, String input2);
    public void onDialogNegativeClick();
}

然后更改onCreateDialog以利用此功能：

     final View view = inflater.inflate(R.layout.dialog_signin, null);
     builder.setView(view) //This layout contains only two EditText, ET1 and ET2.
                .setPositiveButton("adicionar", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {
                        EditText et1 = (EditText) view.findViewById(R.id.et1);
                        EditText et2 = (EditText) view.findViewById(R.id.et2);
                        String input1 = et1.getText().toString();
                        String input2 = et2.getText().toString();
                        mListener.onDialogPositiveClick(input1, input2);
                    }
                })
                .setNegativeButton("cancelar", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int id) {        
                        mListener.onDialogNegativeClick();
                    }
                });
        return builder.create();

然后您的界面实现变为：

@Override
public void onDialogPositiveClick(String input1, String input2) {        
    Toast.makeText(this,"hola " + input1 + " " + input2, Toast.LENGTH_LONG).show();      
}

Answer 3

试试这段代码。

#!/bin/bash
#
#  Make one PDF per page using PDF toolkit.
#  Convert this PDF to SVG using inkscape
#

inputPdf=$1

pageCnt=$(pdftk $inputPdf dump_data | grep NumberOfPages | cut -d " " -f 2)

for i in $(seq 1 $pageCnt); do
    echo "converting page $i..."
    pdftk ${inputPdf} cat $i output ${inputPdf%%.*}_${i}.pdf
    inkscape --without-gui "--file=${inputPdf%%.*}_${i}.pdf" "--export-plain-svg=${inputPdf%%.*}_${i}.svg"
done

我如何获得值EditText一个对话框？

3 个答案: