Question

int main()
{

    // Defining that we only expect there to be a maximum of 1,000
    // characters per lines read.
    char buffer[1000];
    FILE *pFile;
    char numbers = 0;
    char chars = 0;

    // Opens the file for reading
    pFile = fopen("vstup.txt", "r");

    // fopen returns 1 if an error occurred 
    if (!pFile)
        printf("Error : Couldn't Read the File\n");


    while (fgets(buffer, 1000, pFile) != NULL)
    {

        printf("%s", buffer);

        for (int i = 0; i < 50; i++)
        {
            if (buffer[i] >= '0' && buffer[i] <= '9')
            numbers++;

            if ((buffer[i] >= 'A' && buffer[i] <= 'Z') || (buffer[i] >= 'a' && buffer[i] <= 'z'))
                chars++;
        }

    }


    printf("\nSuccess Reading from File\n");
    printf("\nNum of numbers %d",numbers);
    printf("\nNum of letters %d", chars);

    // Closes the text file
    if (fclose(pFile) != 0)
        printf("Error : File Not Closed\n");

    getchar();

}

我正在尝试计算文件中的字母和数字的数量，但它对于数字不起作用，然后我认为我不确定如何正确处理声明而不是浪费计数。

我会感激任何帮助。

Answer 1

Thx伙伴我用fgetc做了一切现在都有效。

do
    {
        c = fgetc(pFile);
        if (feof(pFile))
        {
            break;
        }
        printf("%c", c);
        if (c >= '0' && c <= '9')
            numbers++;

        if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
            chars++;
    } while (1);

Answer 2

由于该程序每行只检查50个字符，因此该程序不太可能准确计算任何内容。

我建议改变：

while (fgets(buffer, 1000, pFile) != NULL)

为：

for (int i = 0; buffer[i] != '\0'; i++)

C计算文件中的数字和字母数

2 个答案: