Question

我一直在尝试使用PHP和MySQL设置登录页面，当我使用带有 - ＆gt;的预准备语句时，我遇到了一个问题。运营商。我正确安装了php5和apache2，phpinfo();运行没有问题，但是当我使用这段代码时：

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>Login</title>
    </head>
    <body>
        <form action="" method="POST">
            <label for="username">Username:</label>
            <br />
            <input type="text" name="username" id="username" />
            <br />
            <label for="password">Password:</label>
            <br />
            <input type="password" name="password" id="password" />
            <br />
            <input type="submit" value="Submit" />
        </form>
        <?php 
            error_reporting(-1);
            ini_set('display_errors', 'On');

            if (isset($_POST['username']) && isset($_POST['password'])) {
                $logged_in = false;

                $username = $_POST['username'];
                $password = $_POST['password'];

                $conn = new mysqli('localhost', 'root', 'password', 'db');

                /* create a prepared statement */
                if ($stmt = $conn->prepare("SELECT username, password, salt FROM `users` WHERE `username` = ?")) {

                    /* bind parameters for markers */
                    $stmt->bind_param("s", $username);

                    /* execute query */
                    $stmt->execute();

                    $stmt->bind_result($storedUser, $storedPassword, $storedSalt);

                    while ($stmt->fetch()) {
                        // $storedUser, $storedPassword, $storedSalt
                        if (crypt($password, $storedSalt) == $storedPassword) {
                            $logged_in = true;
                        }
                    }

                    /* close statement */
                    $stmt->close();

                    if ($logged_in === true) {
                        echo 'Successfully logged in as ' . $username;
                    }
                }
            }

        ?>
    </body>
</html>

php打破＆gt;其余部分显示在页面上。

prepare("SELECT username, password, salt FROM `users` WHERE `username` = ?")) { /* bind parameters for markers */ $stmt->bind_param("s", $username); /* execute query */ $stmt->execute(); $stmt->bind_result($storedUser, $storedPassword, $storedSalt); while ($stmt->fetch()) { // $storedUser, $storedPassword, $storedSalt if (crypt($password, $storedSalt) == $storedPassword) { $logged_in = true; } } /* close statement */ $stmt->close(); if ($logged_in === true) { echo 'Successfully logged in as ' . $username; } } } ?>

Answer 1

虽然我仍然不确定导致此问题的原因，但我通过运行来修复它：

sudo /etc/init.d/apache2 stop
sudo apt-get remove --purge apache2 php5
sudo apt-get remove --purge libapache2-mod-php5
sudo apt-get install php5 apache2 libapache2-mod-php5
sudo /etc/init.d/apache2 start
sudo a2enmod php5
sudo /etc/init.d/apache2 force-reload

感谢大家的帮助。

PHP - ＆gt;函数调用break页面

1 个答案: