Question

我有一个XML产品Feed，我正在使用PHP进行解析，以将产品加载到database.

我需要将每个元素放入$products = array()的数组中，例如：

$products[AttributeID] = value

这是我到目前为止所做的：

我使用的是simplexml，我已经掌握了大部分内容：

    $xml = simplexml_load_file($CatalogFileName) or die("can't open file " . $CatalogFileName);

    foreach($xml->children() as $products) { 
        foreach($products->children() as $product) {
            $new_product = array();
            $new_product[sku] = "AS-" . $product->Name;
            foreach($product->Values->Value as $node) { 
                $node_name = preg_replace('/\s+/', '', $node[AttributeID]);
                $new_product[$node_name] = $node[0];  **<--THIS IS NOT WORKING: $node[0] returns an array I only want the data in each attribute.**
            }
            foreach($product->AssetCrossReference as $node) { 
                $new_product[image] = "http://www.xxxxxxxx.com/images/items/fullsize/" . $node[AssetID] . ".jpg";
            }
            print_r($new_product); 
        }
    }

以下是一个产品节点的图片：XML

有人可以在这里给我一些帮助吗？我做了很多PHP编程，但这是我第一次处理XML

Answer 1

可能的解决方案是使用xpath方法查找<Value>元素。 xpath方法将返回SimpleXMLElement对象的数组。

这些SimpleXMLElement个对象有一个attributes方法，可用于访问“AttributeID”属性。

我希望这个例子可以帮到你：

$xml = simplexml_load_file($CatalogFileName) or die("can't open file " . $CatalogFileName);

$productsArray = array();

foreach($xml->children() as $products) {
    foreach($products->children() as $product) {
        $new_product = array();
        $productId = (string)$product->attributes()->ID;
        $new_product['NAME'] = "AS-" . (string)$product->Name;

        // xpath will return an array of SimpleXMLElement objects
        $values = $product->Values->xpath('//Value');

        // use the attributes method to access the AttributeID
        foreach ($values as $node) {
            $attributeID = (string)$node->attributes()->AttributeID;
            $new_product[$attributeID] = trim((string)$node);
        }

        $new_product['AssetID'] = sprintf(
            "http://www.xxxxxxxx.com/images/items/fullsize/%s.jpg",
            (string)$product->AssetCrossReference->attributes()->AssetID
        );

        // Add $new_product to $productsArray using the $productId as the array key
        $productsArray[$productId] = $new_product;
    }
}

用PHP解析XLM

1 个答案: