捕获ArrayOutOfBoundsException

Question

我正在为我的学校制作一个项目，我已处理所有异常，但我无法处理ArrayOutOfBoundsException。 所以我在stackoverflow上搜索了一个解决方案，它说要使用IndexOutOfBoundsException（链接到解决方案：why is it not catching the arrays out of bound?）  但它没有用。请帮忙？ 这是我的代码：

for (int i = 0; i < 4; i++) {
    System.out.println(fruit[i] + fruitprice[i]);
}
System.out.println("\n" + "please enter the number marked for the icecream you want to buy");
do {
    x = 0;
    try {
        icenum1 = Integer.parseInt( in .readLine()) - 1;
    } catch (NumberFormatException n) {
        System.out.println("please enter in numbers and not in words.... please try again");
        x = 1;
    } catch (IndexOutOfBoundsException e) {
        System.out.println("please enter a number out of the given numbers and not any other number");
        x = 1;
    }
} while (x != 0);
System.out.print("\u000c");
System.out.println("your choice is " + fruit[icenum1]);

Answer 1

如果它仍然尊重代码的逻辑，则将这些行移动到try块中。

System.out.print("\u000c");
System.out.println("your choice is " + fruit[icenum1]);

如果抛出IndexOutOfBoundException，它将来自第二行，因为它将尝试访问当前数组中不存在的索引。