Question

我正在制作一个程序，要求用户输入朋友的姓名，然后询问用户的姓名。然后告诉他们名字中有多少个元音，但我的代码只计算其中一个单词中的元音数：

vowel_list = ["a","e","i","o","u"]
friend_name = input("enter your friends name")
yourname = input("enter your name")

def awesome(yourname,friend_name):
    vowel_count = 0
    friend_name = list(friend_name)
    yourname = list(yourname)
    for i in range(len(yourname)):
        if yourname[i] in vowel_list:
            vowel_count += 1
    return vowel_count
    for i in range(len(friend_name)):
        if me[i] in vowel_list:
            vowel_count += 1
    return vowel_count

print(awesome(yourname,friend_name))

Answer 1

您的函数中有两个return语句。第一个之后的所有代码永远不会被执行。

只需为一个名称编写一个函数：

vowels = set(["a","e","i","o","u"])
def awesome(name):
    vowel_count = 0
    for letter in name:
        if letter in vowels:
            vowel_count += 1
    return vowel_count

并将其用于两个名称：

friend_name = input("enter your friends name")
yourname = input("enter your name")
print(awesome(friend_name))
print(awesome(yourname))

元音只计算一个字？

1 个答案: