Question

我在json中有一个嵌套数组，如下所示：

var json.result= [
{"id":"0","category":"Camera","name":"600D Kit", "condition":"OK"},    
{"id":"1","category":"Camera","name":"600D Kit", "condition":"missing cap"},        
{"id":"2","category":"Camera","name":"7D Kit", "condition":"OK"}]

这就是我要做的事情：
1 /查找数组中的每个“名称”。
2 /打印相应属于“名称”的“id”和“category”的值

理想的结果：
设备id = 0
类别：相机
名称：600D Kit

设备ID = 1
类别：相机
名称：600D Kit

设备ID = 2
类别：相机
名称：7D Kit

这是我的尝试：

var equipmentName = [];
var listLength = json.result.length;
while (listLength--){
    equipmentName[listLength] = json.result[listLength].name
}
console.log(equipmentName);

var equipment = json.result.find(function(e){           
    return e.name == equipmentName;             
});
console.log("equipment id: " + equipment.id);
console.log("category: " +equipment.category);                      
console.log("name: " +equipment.name);

我可以在数组中打印“names”的所有值，并打印return e.name;数组中第一项的“id”，“category”和“name”。但是，一旦我添加return e.name == equipmentName;，我就会收到“设备

的错误

Answer 1

此代码会将所有元素显示到控制台。

var result= [
 {"id":"0","category":"Camera","name":"600D Kit", "condition":"OK"},    
 {"id":"1","category":"Camera","name":"600D Kit", "condition":"missing cap"},        
 {"id":"2","category":"Camera","name":"7D Kit", "condition":"OK"}
];

result.map(function(element){  
  console.log(element.id,element.category,element.name);  
  // Element display functions here
});

jQuery：打印嵌套数组

1 个答案: