Question

我在MySQL中编写了以下SQL语句：

USE my_database;
SELECT * FROM some_table WHERE some_column IN (1, 2, 3);

这将返回一组行，这些行的列值是另一个表的一行中的键（称为some_other_table）。

a b c d <--this is the column with the key
      1
      2
      3

我想说，查找另一个表中值为1的所有行，然后执行某些操作（将某些列置空）

感谢任何帮助。

Answer 1

是的，您可以使用多表UPDATE语法：

UPDATE some_other_table
JOIN   some_table ON (some_table.some_key = some_other_table.id)
SET    some_other_table.some_field = NULL
WHERE  some_table.some_column IN (1, 2, 3);

示例：

CREATE TABLE some_table (id int, some_column int, some_key int);
CREATE TABLE some_other_table (id int, some_field int);

INSERT INTO some_table VALUES (1, 1, 1);
INSERT INTO some_table VALUES (2, 2, 2);
INSERT INTO some_table VALUES (3, 3, 3);
INSERT INTO some_table VALUES (4, 4, 4);
INSERT INTO some_table VALUES (5, 5, 5);

INSERT INTO some_other_table VALUES (1, 10);
INSERT INTO some_other_table VALUES (2, 20);
INSERT INTO some_other_table VALUES (3, 30);
INSERT INTO some_other_table VALUES (4, 40);

在：

SELECT * FROM some_table;
+------+-------------+----------+
| id   | some_column | some_key |
+------+-------------+----------+
|    1 |           1 |        1 |
|    2 |           2 |        2 |
|    3 |           3 |        3 |
|    4 |           4 |        4 |
|    5 |           5 |        5 |
+------+-------------+----------+
5 rows in set (0.00 sec)

SELECT * FROM some_other_table;
+------+------------+
| id   | some_field |
+------+------------+
|    1 |         10 |
|    2 |         20 |
|    3 |         30 |
|    4 |         40 |
+------+------------+
4 rows in set (0.00 sec)

后：

SELECT * FROM some_table;
+------+-------------+----------+
| id   | some_column | some_key |
+------+-------------+----------+
|    1 |           1 |        1 |
|    2 |           2 |        2 |
|    3 |           3 |        3 |
|    4 |           4 |        4 |
|    5 |           5 |        5 |
+------+-------------+----------+
5 rows in set (0.00 sec)

SELECT * FROM some_other_table;
+------+------------+
| id   | some_field |
+------+------------+
|    1 |       NULL |
|    2 |       NULL |
|    3 |       NULL |
|    4 |         40 |
+------+------------+
4 rows in set (0.00 sec)

更新：继续以下评论。

另一个例子：

CREATE TABLE amir_effective_reference (class int, inst int, rln int, rclass int, rinst int, chg int, typ int);
CREATE TABLE amir_effective_change (chg int, txn int, rltn int, entry int, effective int);

INSERT INTO amir_effective_reference VALUES (1, 100, 1, 50, 20, 10, 5000);
INSERT INTO amir_effective_change VALUES (10, 100, 100, 500, 200);

结果：

UPDATE amir_effective_change 
JOIN   amir_effective_reference ON (amir_effective_reference.chg = amir_effective_change.chg) 
SET    amir_effective_change.effective = NULL 
WHERE  amir_effective_change.rltn IN (100);

SELECT * FROM amir_effective_change;
+------+------+------+-------+-----------+
| chg  | txn  | rltn | entry | effective |
+------+------+------+-------+-----------+
|   10 |  100 |  100 |   500 |      NULL |
+------+------+------+-------+-----------+
1 row in set (0.00 sec)

帮助MySQL语句

1 个答案: