我在尝试从两个日历选择中获取日期时遇到基本问题,并将它们放入下面的计算中。
任何人都有解决方案吗?
由于 伊恩
<body>
<h1>Project Details</h1>
<h3>Please enter the project Notice to Proceed (NTP) date: <input id="NtpDate" type= "date" name="NtpDate"></h3>
</br>
<h3>Please enter the Report date: <input type= "date" name="ReportDate"> </h3>
<script type="text/javascript">
// I would like to replace this with the <input type = date> tags ...var NtpDate = new Date("7/11/2004");
// I would like to replace this with the <input type = date> tags ... var ReportDate = new Date("12/12/2010");
var timeDiff = Math.abs(ReportDate.getTime() - NtpDate.getTime());
var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24));
//alert(diffDays);
document.write("Period =" + diffDays + " (Days from NTP)");
</script>`
</body>
&#13;
答案 0 :(得分:0)
重复问题How to calculate date difference in javascript
但这就是你获得两个datepicker的价值的方法。
var ReportDate = document.getElementById('ReportDate').value;
答案 1 :(得分:0)
您可以尝试以下方式:
<h3>Please enter the project Notice to Proceed (NTP) date: <input id="NtpDate" type= "date" name="NtpDate"></h3>
<h3>Please enter the Report date: <input type= "date" name="ReportDate" id="abc"></h3>
$("#abc").on("change", function () {
var olddate = new Date($("#NtpDate").val());
var newdate = new Date($(this).val());
var timeDiff = Math.abs(newdate.getTime() - olddate.getTime());
var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24));
alert(diffDays);
});
<强> DEMO FIDDLE 强>
答案 2 :(得分:0)
<body>
<h1>Project Details</h1>
<h3>Please enter the project Notice to Proceed (NTP) date: <input id="NtpDate" type= "date" name="NtpDate"></h3>
</br>
<h3>Please enter the Report date: <input id="ReportDate" type= "date" name="ReportDate" onchange="myFunction()"> </h3>
<script type="text/javascript">
myFunction = function(){
alert(document.getElementById("NtpDate").value +" >> "+document.getElementById("ReportDate").value)
var NtpDate = new Date(document.getElementById("NtpDate").value);
var ReportDate = new Date(document.getElementById("ReportDate").value);
var timeDiff = Math.abs(ReportDate.getTime() - NtpDate.getTime());
var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24));
//alert(diffDays);
alert("Period =" + diffDays + " (Days from NTP)");}
</script>`
</body>
答案 3 :(得分:0)
时刻就像:
moment('some date').diff('other date', 'days')