Question

我正在尝试通过c＃

中的浏览按钮为我的电子邮件添加附件

这是我的代码：

string fileName = Path.Combine(Path.GetTempPath(),FileUploadControl.FileName);
using (FileStream fs = File.Open(fileName, FileMode.Create, FileAccess.Write, FileShare.Read))
{
    byte[] buffer = new byte[1024];
    int bytesRead; while ((bytesRead = fs.Read(buffer, 0, buffer.Length)) > 0) 
    {
        fs.Write(buffer, 0, bytesRead);
    }
}

Attachment attachment = new Attachment(fileName);
msg.Attachments.Add(attachment);

$ exception {“Stream不支持读取。”} System.Exception {System.NotSupportedException}

我做错了什么？

Answer 1

我的印象是FileUpload.FileName返回客户端端的文件名，而不是服务器端。您可能需要FileUpload.FileBytes，这是一个byte []数组。

string fileName = Path.Combine(Path.GetTempPath(),FileUploadControl.FileName);
using (FileStream fs = File.Open(fileName, FileMode.Create, FileAccess.Write))
{
    fs.Write(FileUploadControl.FileBytes, 0, FileUploadControl.FileBytes.Length);
}

Attachment attachment = new Attachment(fileName);
msg.Attachments.Add(attachment);

Answer 2

您正在从同一个文件中读取和写入。请查看http://msdn.microsoft.com/en-us/library/system.web.ui.webcontrols.fileupload.saveas.aspx

上的示例

Answer 3

你很亲密。您打算从文件输入流中读取但不是：

string fileName = Path.Combine(Path.GetTempPath(),FileUploadControl.FileName);
using (FileStream fs = File.Open(fileName, FileMode.Create, FileAccess.Write, FileShare.Read))
{
    byte[] buffer = new byte[1024];
    int bytesRead; while ((bytesRead = FileUploadControl.PostedFile.InputStream.Read(buffer, 0, buffer.Length)) > 0) 
    {
        fs.Write(buffer, 0, bytesRead);
    }
}

Attachment attachment = new Attachment(fileName);
msg.Attachments.Add(attachment);

Answer 4

Attachment attachment = new Attachment(FileUploadControl.FileName);
msg.Attachments.Add(attachment);

就是你所需要的一切。

从浏览按钮添加电子邮件附件

4 个答案: