我正在使用Codeigniter 3,我试图获取xml的值。我没办法......
我尝试使用此代码获取值。
$dom = new DOMDocument();
$dom->loadlXML($xml);
$img = $dom->getElementsByTagName('sonucKodu')->item(0);
echo $img->attributes->getNamedItem("value")->value;
我的xml文件。
<?xml version="1.0" encoding="UTF-8"?>
<SYSMessage xmlns:ext="http://nxxx/Cd/Extensions/1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<messageType code="1" value="xxx" codeSystemGuid="0a9ba485-e7e0-4abb-9c86-0a14fd364bb8" version="1" />
<documentGenerationTime value="201512041717" />
<author>
<healthcareProvider code="0" value="SYS" codeSystemGuid="c9dbe1cb-57cb-48fb-bdd3-d622e0e304c6" version="1" />
</author>
<recordData>
<KayitCevabi>
<sonucKodu value="E2003" />
<sonucMesaji value="TakipNo geçerli değil" />
</KayitCevabi>
</recordData>
</SYSMessage>
我只需要属性sonucKodu
的值。它必须是E2003
。
感谢您的帮助。
答案 0 :(得分:1)
我使用的是SimpleXMLElement而不是Domdocument。
$xml = '<?xml version="1.0" encoding="UTF-8"?>
<SYSMessage xmlns:ext="http://nxxx/Cd/Extensions/1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<messageType code="1" value="xxx" codeSystemGuid="0a9ba485-e7e0-4abb-9c86-0a14fd364bb8" version="1" />
<documentGenerationTime value="201512041717" />
<author>
<healthcareProvider code="0" value="SYS" codeSystemGuid="c9dbe1cb-57cb-48fb-bdd3-d622e0e304c6" version="1" />
</author>
<recordData>
<KayitCevabi>
<sonucKodu value="E2003" />
<sonucMesaji value="TakipNo geçerli değil" />
</KayitCevabi>
</recordData>
</SYSMessage>';
$s_xml = new SimpleXMLElement($xml);
//print_r($s_xml);
echo $s_xml->recordData->KayitCevabi->sonucKodu['value'];
输出:
E2003
答案 1 :(得分:0)
<?php
$myXMLData =
"<?xml version='1.0' encoding='UTF-8'?>
<note>
<to>Tove</to>
<from>Jani</from>
<heading>Reminder</heading>
<body>Don't forget me this weekend!</body>
</note>";
$xml=simplexml_load_string($myXMLData) or die("Error: Cannot create object");
print_r($xml);
?>