Question

伙计们当我点击一个按钮并制作该代码时，我试图获取随机值，但当我点击某种方式时，一个值重复4次，如＆＃34; k0k2k4k6＆＃34; ，＆＃34; n0n2n4n6＆＃34;。为什么会发生这种情况？这不是巧合。提前致谢！ JSFIDDLE

＆＃13;

  private AsyncHttpClientConfig cfg = new AsyncHttpClientConfig.Builder( ).
                setConnectTimeout( 20000 ).
                setRequestTimeout( 20000 ).
                setWebSocketTimeout(20000).
                setMaxRequestRetry(3).
                setReadTimeout( 20000 ).
                setAcceptAnyCertificate( true ).
                build( )

   private AsyncHttpClient = new AsyncHttpClient( cfg )


  client.prepareGet( url ).
                 setProxyServer( new ProxyServer( ProxyServer.Protocol.HTTP, "myproxyurl", 2222, "principal", "password" ) ).
                 execute( ).
                 get()

＆＃13;

$(function() {
  var words = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz"
  var word = words[Math.floor(Math.random() * words.length)];
  var myLength = 8;

  function random() {
    for (var i = 0; i < myLength; i++) {
      $('#content').append(word + i++);
    }
  }

  $('#button').click(function() {
    random();
  });

});

＆＃13;

#content {
  width: 200px;
  height: 50px;
  border: 1px solid #333;
  margin-top: 50px;

＆＃13;

Answer 1

为什么会产生4次？

因为你的最大限制是8而你正在递增两次，一个在word循环中，在那里。

在循环中移动$(function() { var words = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz" var myLength = 8; function random() { // Also I would clear before generating new: $('#content').html(""); for (var i = 0; i < myLength; i++) { var word = words[Math.floor(Math.random() * words.length)]; $('#content').append(word + i++); } } $('#button').click(function() { random(); }); });（生成的动态）定义解决了它：

#content {
  width: 200px;
  height: 50px;
  border: 1px solid #333;
  margin-top: 50px;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="button">Click</button>
<div id="content"></div>

pattern = """
        P2: {<JJ>+ <RB>? <JJ>* <NN>+ <VB>* <JJ>*}
        P1: {<JJ>? <NN>+ <CC>? <NN>* <VB>? <RB>* <JJ>+}
        P3: {<NP1><IN><NP2>}
        P4: {<NP2><IN><NP1>}

    """

Answer 2

将变量移动到函数中：

JasperPrint

Answer 3

试试这个

$(function() {
  var words = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXTZabcdefghiklmnopqrstuvwxyz"
  var myLength = 8;

  function random() {
    var word = words[Math.floor(Math.random() * words.length)];

    for (var i = 0; i < myLength; i++) {
      $('#content').append(word + i++);
    }
  }

  $('#button').click(function() {
    $('#content').html('');
    random();
  });

});

用javascript获取随机值

3 个答案: