如何将2个参数传递给php中的array_map函数？

Question

$sql="select * from question_test where test_id='".$test_id."'   and  difficulty_level   BETWEEN  ".$_SESSION['difficulty_start']." and  ".$_SESSION['difficulty_end']." and question_id NOT IN ('".implode("', '", array_map('mysqli_real_escape_string', $_SESSION['question_attempt']))."')  order by rand()*favourability_level  desc";

运行上面的代码时出现错误：

  

警告：mysqli_real_escape_string（）正好需要2个参数，1在第359行的C：\ xampp \ htdocs \ exam.php中给出

Answer 1

使用回调函数

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其中function array_map_callback($a) { global $con; return mysqli_real_escape_string($con, $a); } array_map('array_map_callback', $_SESSION['question_attempt']); 是连接变量。

所以你的$con变量将是：

$sql

或者您可以使用array_walk

$sql="select * from question_test where test_id='".$test_id."' and  difficulty_level BETWEEN  ".$_SESSION['difficulty_start']." and  ".$_SESSION['difficulty_end']." and question_id NOT IN ('".implode("', '", array_map('array_map_callback', $_SESSION['question_attempt']))."')  order by rand()*favourability_level  desc";