Question

我是Jersey测试框架的新手。我正在尝试使用我的项目中的泽西测试框架来实现测试用例。我有一个REST服务，其URL将是：

http://localhost:8080/EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==

我尝试使用Jersey使用以下代码测试此服务：

public class DealerServicesTest extends JerseyTest{
@Override
protected AppDescriptor  configure() {
    return new WebAppDescriptor.Builder().build();
}

@Test
public void testGetDealerDetails() throws JSONException,URISyntaxException {
    WebResource webResource = client().resource("http://localhost:8080/");
    JSONObject json = webResource.path("EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==").get(JSONObject.class);

    assertEquals("ONLINE", json.get("companyType"));
    assertEquals("FabFurnish", json.get("companyName"));        
    assertEquals("Gurgoan,Haryana, India", json.get("companyAddress"));
    assertEquals("04222456803", json.get("phoneNumber"));
    assertEquals("ACTIVE", json.get("status"));     
    assertEquals("customerservice@fabfurnish.com", json.get("emailId"));
}
}

当我测试邮递员（Chrome扩展程序）的服务时，我得到如下正确的回复：

{
  "companyType": "ONLINE",
  "companyName": "FabFurnish",
  "companyAddress": "Gurgoan,Haryana, India",
  "companyLocation": null,
  "longitude": "77.023419",
  "phoneNumber": "04222456803",
  "serviceRating": 0,
  "repairRating": 0,
  "warrantyRating": 0,
  "shopRating": 0,
  "status": "ACTIVE",
  "createdOn": 1446613095557,
  "updatedOn": 1446613095557,
  "companyId": "FAB",
  "lattitde": "28.47427",
  "emailId": "customerservice@fabfurnish.com",
  "createdby": null,
  "updatedby": null
}

但是通过这个测试我得到以下例外：

com.sun.jersey.api.client.ClientHandlerException:     com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "companyType" (class org.json.JSONObject), not marked as ignorable (0 known properties: ])
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@45b4c3a9; line: 1, column: 17] (through reference chain: org.json.JSONObject["companyType"])
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:563)
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:506)
    at com.sun.jersey.api.client.WebResource.handle(WebResource.java:674)
    at com.sun.jersey.api.client.WebResource.get(WebResource.java:191)
    at com.vs.mhs.ezsupport.services.DealerServicesTest.testGetDealerDetails(DealerServicesTest.java:27)

任何人都可以帮我找出原因？

编辑：我的代码如下所示：

@PermitAll
@GET
@Path("/getdealerdetails/{companyId}/{token_id}")
public Response getDealerDetails(@PathParam("companyId") String companyId, @Context SecurityContext userContext, @Context HttpServletRequest request){
    boolean isUserAuthorised = isUserAuthenticated(userContext);
    DealerDetails dealer = null;
    DealerDetailsView getDealerView = null;
    if(isUserAuthorised){
        EntityManager em = (EntityManager) request.getAttribute(FilterConstants.ENTITYMANAGER);
        DealerDetailsBDL dealerbdl = new DealerDetailsBDL(em);
        dealer = dealerbdl.getDealerDetails(companyId);
        getDealerView = new DealerDetailsView(dealer);
    }
    return Response.ok(getDealerView).build();          
}

DealerDetailsView是一个包含私有变量的类，用于下面列出的属性以及getter和setter：

private String companyid;
private String companyType;
private String companyName;
private String companyAddress;
private String companyLocation;
private String lattitude;
private String longitude;
private String phoneNumber;
private String emailid;
private int serviceRating;
private int repairRating;
private int warrantyRating;
private int shopRating;
private String status;

Answer 1

杰克逊是JSON提供商，杰克逊通常使用模型POJO，JSONObject不是。杰克逊正在寻找companyType的{{1}}财产，但却没有。这就是你得到例外的原因。如果您没有专门针对该JSON的POJO，那么只需将其作为String，并使用该字符串创建JSONObject

JSONObject

更新

Jackson的POJO只是一个将JSON字段映射到类属性的类（遵循JavaBean namming约定）。例如，对于这两个JSON字段

String jsonString = webResource...get(String.class);
JSONObject json = new JSONObject(jsonString);

您可以拥有类似

的课程

"companyType": "ONLINE",
"companyName": "FabFurnish"

要将JSON字段与Java属性相匹配，属性（getter / setter）应该以{{1}}为前缀，并且字段的确切名称，首字母大写，如上所示。因此，只需使用所有其他JSON字段完成POJO，序列化应与public class CompanyInfo { private String companyType; private String companyName; public CompanyInfo() {} public String getCompanyInfo() { return companyInfo; } public void setCompanyInfo(String info) { this.companyInfo = info; } public String getCompanyType() { return companyType; } public void setCompanyType(String type) { this.companyType = type; } }一起使用。

Jersey Test Framework中的UnrecognizedPropertyException

1 个答案:

更新