Spring 3中的Dispatcher Servlet映射错误

时间:2015-12-04 06:01:07

标签: spring spring-mvc spring-3

我需要单独在春季3运行这个项目。我不能使用弹簧靴或任何其他技术堆栈。

我曾尝试编写一个简单的hello world应用程序,但是我收到了404错误。

我的文件如下所示。

的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

弹簧servlet.xml中

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
        http://www.springframework.org/schema/mvc 
        http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.2.xsd">

    <context:component-scan
        base-package="com.hpe" />
    <mvc:annotation-driven />

    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/jsp/" />
        <property name="suffix" value=".jsp" />
    </bean>
</beans>

HelloWorldController.java

package com.hpe;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class HelloWorldController {

    @RequestMapping(value = "/hello", method = RequestMethod.GET)
    public ModelAndView sayHello() {
        String message = "Hello World, Spring 3.0!";
        return new ModelAndView("hello", "message", message);
    }
}

的hello.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
        <title>Insert title here</title>
    </head>
    <body>
        <h1>Hello World</h1>    
    </body>
</html>

每当我尝试访问localhost:8080 / {context-name} / hello时,我都会收到404错误。

3 个答案:

答案 0 :(得分:0)

你试着这么简单,并告诉我它工作不是

@RequestMapping(value = "/hello", method = RequestMethod.GET)
    public String sayHello() {
        return "hello";
    }

答案 1 :(得分:0)

@RequestMapping("/")上添加HelloWorldController班级注释。

答案 2 :(得分:0)

代码对我来说是正确的。尝试

1)验证您的上下文根 - &gt; http://localhost:8090/%nameofwar %/你好

2)检查战争是否正确建造。检查所有必需的工件,如web.xml,jsp,.class,.xml是否在正确的位置

3)在独立的Tomcat中部署并检查