(已编辑)现在我修复了上一个错误,但收到了错误:
路径中的非法字符。
我正在尝试迭代一些json构建一个无序的链接列表。我在显示模板中有<div ng-repeat="item in shifts">
<div ng-show="item.PublishedEmployee.Id == currentId">
Matched
</div>
</div>
语句,在视图中有@for
。这是我的代码:
控制器:
Html.DisplayFor
查看:
using System;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System.Collections.Generic;
using System.Data;
using System.IO;
using System.Linq;
using System.Web;
using System.Web.Mvc;
namespace app.Web.Areas.Admin.Controllers
{
public class CommonReportsController : Controller
{
public ActionResult CommonReports(Guid orgId)
{
JObject TopListData = JObject.Parse(System.IO.File.ReadAllText(@"C:\Dev\app\app.Web\json\TopListData.json"));
string cData = Newtonsoft.Json.JsonConvert.SerializeObject(TopListData);
var TopListDataView = TopListData;
return View(TopListDataView);
}
}
}
显示模板:
@model app.API.Models.CommonReports.CommonReportsModel
@using app.API.Resources;
@using app.Web.Utility;
@{
ViewBag.Title = Text.Get(Text.eTextType.Label, @Text.Get(Text.eTextType.Label, "CommonReports_Title"));
}
@section BreadCrumbTitle {
@( Text.Get(Text.eTextType.Tab, @Text.Get(Text.eTextType.Label, "CommonReports_Title")))
}
<div class="titletop">@ViewBag.Title</div>
<div id="CommonReportsList">
@Html.DisplayFor(m => m.CommonReports, "CommonReportsDisplayTemplate")
</div>
型号:
@model app.API.Models.CommonReports.CommonReportsModel
@using app.API.Resources;
<ul class="row-centered-list">
@for (var i = 0; i < 1; i++)
{
<li><img src="~/Images/document.png" /> @Html.ActionLink(@Text.Get(Text.eTextType.Label, TopListDataView[i].ListLabel), TopListDataView[i].ListView, TopListDataView[i].ListController, null, new { data_toggle = "tooltip", data_original_title = TopListDataView[i].ListToolTip })<span class="newRed"> - @Text.Get(Text.eTextType.Label, "CommonReports_New")</span></li>
}
</ul><br />
我在这里做错了什么?
答案 0 :(得分:1)
尝试控制器上的代码
public ActionResult CommonReports(Guid orgId)
{
var jsonReader = new StreamReader(Server.MapPath("C:\Dev\app\app.Web\json\TopListData.json"));//Your Json File Path
var rawJson = jsonReader.ReadToEnd();
jsonReader.Close();
var TopListDataView = Newtonsoft.Json.JsonConvert.DeserializeObject<List<TopListData>>(rawJson);//Get List Of all Data Json File And TopListData Name As Model Class
return View(TopListDataView);
}
答案 1 :(得分:0)
事实证明,不需要处理Json。我将获得.net对象,所以不需要弄明白。