Question

我有一个数据库，我希望能够搜索一个名称，即如果名称是Mark Kram，它将显示具有该名称的用户，我不需要它是名称为“Mark”的每个人或“Kram”，但只输入字符串。我当前的代码，只显示每个用户而不是我搜索的用户？

（根据评论进行编辑以删除多余的代码）

  find = str(input("Enter the name of the employee you would like to search for: "))
  print()
  for find in record:
      print("Employee Name: " + find[0])
      print("Job title: " + find[1])
      #more prints

Answer 1

您必须在每个元组中的第一个项目（全名）上查找匹配项。

elif choice == "c":
    find = str(input("Enter the name of the employee you would like to search for: "))
    print()
    for employee in record:
        if employee[0] == find:
            print("Employee Name: " + employee[0])
            print("Job title: " + employee[1])
            print("Full time: " + employee[2])
            print("Hourly Rate: " + employee[3])
            print("Years of service: " + str(employee[4]))
            print()

您的代码是开始了解class es。

的一个很好的例子

Answer 2

根据记录的数量，我会采用简单的路线并遍历记录，查找员工的姓名：

empName = "Mark Kram"
for record in records:
  if record[0] == empName:
    print "we found the employee!"
    print record #print the whole employee record

Answer 3

那是因为你在没有任何条件的情况下迭代你的所有记录和打印。您还要立即覆盖查询字符串。

elif choice == "c":
    find = str(input("Enter the name of the employee you would like to search for: "))
    print()
    for employee in record:
        if employee[0] == find:
            print("Employee Name: " + employee[0])
            print("Job title: " + employee[1])
            print("Full time: " + employee[2])
            print("Hourly Rate: " + employee[3])
            print("Years of service: " + str(employee[4]))
            print()

Python在嵌套元组中查找字符串

3 个答案: