Question

这就是这段代码的作用：允许用户输入一个字符（L或S）和三个100到1000之间的整数。程序输出以下内容：

如果使用方法CheckInput在区间[100-1000]中未包含数字，则显示消息：“输入错误！”
如果用户使用方法Largest;
如果用户使用Smallest方法输入字母S，则为最小数字;
使用方法Backwards;
使用方法EvenOrOdd取一个整数，如果数字为偶数则输出'True'，如果是奇数则输出'False'，输出输入的数字后跟'True'或'False'
使用方法CheckDivisor，它接受所有三个数字，并检查第一个数字是否为第二个或第三个的除数，并返回“True”或“False”
使输出更容易理解，并为程序添加两个方法

对于数字7，我添加了，加倍和总和

import java.util.Arrays;
import java.util.Scanner;

public class Words {


    public static void main(String[] args) {
        Scanner scan = new Scanner(System. in );

        while (scan.hasNext()) {
            String line = scan.nextLine();

            if (line.equals("exit")) {
                break;
            }
            String[] words = line.split(" ");

            //alphabetical
            System.out.print("Alphabetical order: ");
            alphabetical(words);
            // concatenate and mix
            String[] sorted = words.clone();
            Arrays.sort(sorted);
            String all = "";
            for (String s: sorted) {
                all += s;
            }

            System.out.println("All together: " + all);
            System.out.println("Concatenate and Mix: " + mix(all));

            // find first 2 and last 2 letters
            first2last2(all);
            //middlexx
            System.out.println("Replace middle with xx or yy: " + middlexx(all));

            System.out.println();
        }
    }
    private static void alphabetical(String[] words) {
        String[] ws = words.clone();
        Arrays.sort(ws);

        for (int i = 0; i < ws.length; i++) {
            if (i != 0) {
                System.out.print(" ");
            }
            System.out.print(ws[i]);
        }
        System.out.println();
    }
    private static String mix(String s) {
        return s.replaceAll("a|e|i|o|u", "x");
    }
    private static void first2last2(String s) {
        if (s.length() < 5) {
            System.out.println("Invalid command!");
        } else {
            System.out.println("First two characters: " + s.substring(0, 2));
            System.out.println("Last two characters: " + s.substring(s.length() - 2, s.length()));
        }
    }
    private static String middlexx(String s) {
        if (s.length() % 2 == 0) {
            return s.substring(0, s.length() / 2) + "xx" + s.substring(s.length() / 2, s.length());
        } else {
            return s.substring(0, s.length() / 2) + "yy" + s.substring(s.length() / 2 + 1, s.length());
        }
    }

}

我如何将其转换为JOptionPane课程？我希望程序要求用户输入L或S，并使用以下内容键入3个整数：

String input1 = JOptionPane.showInputDialog("Please enter L or S");
a = Double.valueOf(input1).doubleValue();

Answer 1

您可以像这样

从JOptionPane获取输入

JOptionPane.showInputDialog ( "put your message here" );

示例代码

  Object[] possibilities = {"ham", "spam", "yam"};
  String s = (String)JOptionPane.showInputDialog(
                      frame,
                      "Complete the sentence:\n"
                      + "\"Green eggs and...\"",
                      "Customized Dialog",
                      JOptionPane.PLAIN_MESSAGE,
                      icon,
                      possibilities,
                      "ham");

  //If a string was returned, say so.
  if ((s != null) && (s.length() > 0)) {
      setLabel("Green eggs and... " + s + "!");
      return;
  }

  //If you're here, the return value was null/empty.
  setLabel("Come on, finish the sentence!");

更多信息：https://docs.oracle.com/javase/tutorial/uiswing/components/dialog.html

Java Scanner类到JOptionPane类？

1 个答案: