Question

我尝试将一些数据插入数据库。首先，我确保我有数据。我找不到原因，为什么没有插入数据。

echo 'os_id = ', $os_id, ' os_shoph = ', $os_shoph, ' os_shopd = ',  $os_shopd;

        $insert = $db->prepare("INSERT `f2go`.`prints` ("
                    . "prt_os_id, prt_ts, prt_shoph, prt_shopd)"
                    . "VALUES (?, NOW(), ?, ? )");

        $insert->bind_param('iss',
                $os_id,
                $os_shoph, 
                $os_shopd); 

        if($insert->execute()) {
            echo '<h1>Print new order ', $os_id, '</h1>';
        } else {
            echo '<h1>Re-print order ', $os_id, '</h1>';
        }      
    }

我添加了错误检查。

if (!($insert = $db->prepare("INSERT `f2go`.`prints` ("
                        . "prt_os_id, prt_ts, prt_shoph, prt_shopd)"
                        . "VALUES (?, NOW(), ?, ? )"))) {
    echo "Prepare failed: (" . $db->errno . ") " . $db->error;
}
if (!$insert->bind_param("iss", $os_id, $os_shoph, $os_shopd)) {
    echo "Binding parameters failed: (" . $insert->errno . ") " . $insert->error;
}
if (!$insert->execute()) {
    echo "Execute failed: (" . $insert->errno . ") " . $insert->error;
}

结果是：

os_id = "206" os_shoph = 0228099392 os_shopd = example 
Re-print order "206" 
Execute failed: (1062) Duplicate entry '0' for key 'prt_os_id'

数据库列os_id设置为'unique' 我无法弄清楚为什么os_id = 206会被视为'0'

Answer 1

在'prt_os_id'字段中插入'iss'值，它似乎是一个整数字段。这个错误执行失败：（1062）键'prt_os_id'重复输入'0' 参考插入查询将“0”值放在键prt_os_id中，当这种情况发生两次时，会显示此错误，那么为什么要插入“0”值？因为绑定中传递的第一个值是'iss'，它是字符串值。它应该是：

$insert->bind_param("1", $os_id, $os_shoph, $os_shopd))
$insert->bind_param("2", $os_id, $os_shoph, $os_shopd))
$insert->bind_param("3", $os_id, $os_shoph, $os_shopd))
$insert->bind_param("4", $os_id, $os_shoph, $os_shopd))

等等。

Answer 2

只需删除$os_id !!

中的引号即可

测试

<?php
  $os_id ='"206"';
  echo 'os_id = '.intval($os_id).'<br />';
  $os_id ="206";
  echo 'os_id = '.intval($os_id).'<br />';
  $os_id =206;
  echo 'os_id = '.$os_id.'<br />';
  $os_id ="206";
  echo 'os_id = '.$os_id.'<br />';
  echo '-------------------------------------------------------------------------<br />';
  $os_id ='"206"';
  $os_id =trim($os_id, '"');
  echo 'os_id = '.$os_id;
?>

输出

os_id = 0
  os_id = 206
  os_id = 206
  os_id = 206

os_id = 206

在重复键中插入mysql结果

2 个答案: