Question

对象资源表：

ObjectID|Resource

01     | Resource A
01     | Resource B

对象可用性表：

AvailID|DayName

01     | Monday
02     | Tuesday

ObjectResourceAvailability表：

ObjectID|Resource Name|Day

01      |ResourceA    | 01

理想情况下应该显示

ObjectID|Resource Name|DayName

01      |ResourceA, ResourceB    | Monday, Tuesday

我还连接了具有相同ID的列。如何才能使最终结果显示在周一而不是01？我已经尝试选择ObjAvail.DayName并更改连接字符串解决方案，但我一直在选择列表中使列无效，因为它不包含在聚合函数或GROUP BY子句中。

这是帮助我实现连接列的解决方案

  SELECT
        t1.oid
            ,STUFF(
                       (SELECT
                            ', ' + t2.resource
                            FROM objectresource t2
                            WHERE t1.oid=t2.oid
                            ORDER BY t2.resource
                            FOR XML PATH(''), TYPE
                       ).value('.','varchar(max)')
                       ,1,2, ''
                  ) AS Resources
                  ,STUFF(
    (
        SELECT
            ',',
            CAST(availyid AS VARCHAR)
        FROM objectAvail t2
        WHERE t1.oid = t2.oId
        FOR XML PATH('')
    ), 1, 1, '') as [Days]
        FROM objectresource t1
        GROUP BY t1.oid

Answer 1

我得到了它的工作（：

import csv
def main():
    file_contents = []
    with open('flights_table_all.csv', 'rb') as csvfile:
        reader = csv.DictReader(csvfile)    
        for row in reader:
            file_contents.append(row)
        leaders = myfunc(file_contents)


def myfunc(reader):
    count = 0
    for row in reader:
        count = count + 1
    print "ONE: " + str(count)
    myfunc_two(reader)


def myfunc_two(reader):
    count = 0
    for row in reader:
        count = count + 1
    print "TWO: " + str(count)


if __name__ == '__main__':
        main()

SQL - 从另一个表获取值

1 个答案: