我一直按以下方式打印我程序的一些输出:
a=[1,2,3]
b=[10,20,30]
c=[101,201,301]
d=[1010,2010,3010]
results = {'a':a,'b':b,'c':c,'d':d}
print str("First result: ").center(20), str("Second result: ").center(20), str("Third result: ").center(20), str("Fourth result: ").rjust(20)
print
for i in xrange(len(results)):
print repr(float("{0:.2f}".format(results['a'][i]))).center(20),\
repr(float("{0:.2f}".format(results['b'][i]))).center(20),\
repr(float("{0:.2f}".format(results['c'][i]))).center(20),\
repr(float("{0:.2f}".format(results['d'][i]))).center(20)
给出了以下不错的输出:
First result: Second result: Third result: Fourth result:
1.0 10.0 101.0 1010.0
2.0 20.0 201.0 2010.0
3.0 30.0 301.0 3010.0
但现在让我说我有一些未定义的结果,我怎么能写出相同类型的输出呢?
感谢。
答案 0 :(得分:2)
您可以PrettyTable使用pip进行安装,并按如下方式显示您的数据:
x = PrettyTable(["City name", "Area", "Population", "Annual Rainfall"])
x.align["City name"] = "l" # Left align city names
x.padding_width = 1 # One space between column edges and contents (default)
x.add_row(["Adelaide",1295, 1158259, 600.5])
x.add_row(["Brisbane",5905, 1857594, 1146.4])
x.add_row(["Darwin", 112, 120900, 1714.7])
x.add_row(["Hobart", 1357, 205556, 619.5])
x.add_row(["Sydney", 2058, 4336374, 1214.8])
x.add_row(["Melbourne", 1566, 3806092, 646.9])
x.add_row(["Perth", 5386, 1554769, 869.4])
print x
+-----------+------+------------+-----------------+
| City name | Area | Population | Annual Rainfall |
+-----------+------+------------+-----------------+
| Adelaide | 1295 | 1158259 | 600.5 |
| Brisbane | 5905 | 1857594 | 1146.4 |
| Darwin | 112 | 120900 | 1714.7 |
| Hobart | 1357 | 205556 | 619.5 |
| Melbourne | 1566 | 3806092 | 646.9 |
| Perth | 5386 | 1554769 | 869.4 |
| Sydney | 2058 | 4336374 | 1214.8 |
+-----------+------+------------+-----------------+
但在您的情况下,您可以使用add_column()方法将列表作为参数传递。