Question

我有loadData（）函数，它解析大XML文件并将数据插入QTableWidget。应用程序启动时执行功能= GUI暂停冻结，我不希望这样。这是我的WorkerThread类：

class WorkerThread(QThread):

def __init__(self):
    QThread.__init__(self)

def __del__(self):
    self.wait()

def run(self):
    QtApp().loadData()

这就是我的尝试：

class QtApp(QMainWindow):

def __init__(self):

    QMainWindow.__init__(self)


    self.ui = uic.loadUi('gui.ui', self)

    self.ui.show()


    self.workerThread = WorkerThread()
    self.workerThread.start()

它只是一次又一次地加载主窗口。最终应用程序崩溃。在loadData（）结束时退出workerThread也无济于事。

Answer 1

这是一个可能的解决方案：

class WorkerThread(QThread):
    # define a new signal which will be emitted when data loading finishes
    load_data_finished = pyqtSignal(list)

    def __init__(self):
        QThread.__init__(self)

    def run(self):
        # load data in new thread
        self.load_data()

    def load_data(self):
        data = []
        #
        # load your data here ...
        # example:
        data.append(1)
        data.append(2)
        data.append(3)
        #
        # when loading data finishes, emit the signal
        self.load_data_finished.emit(data)


class QtApp(QMainWindow):
    def __init__(self):
        QMainWindow.__init__(self)
        # load UI...
        self.show()

        self.workerThread = WorkerThread()
        # connect the thread signal to a slot defined in this class
        self.workerThread.load_data_finished.connect(self.on_load_data_finished)
        self.workerThread.start()

    def on_load_data_finished(self, data):
        print("data loaded: ", data)


app = QApplication(sys.argv)
main_window = QtApp()

app.exec _（）

应用程序启动时如何使用QThread

1 个答案: