Question

SELECT * FROM TABLE@dblink1

该文件为

f = open(document) #this will open the selected class data
swag = [f.readline(),f.readline(),f.readline(),f.readline(),f.readline(),f.readline()] #need to make go on for amount of line

viewfile = input("Do you wish to view the results?")#This will determine whether or not the user wishes to view the results
if viewfile == 'yes': #If the users input equals yes, the program will continue
order = input("What order do you wish to view to answers? (Alphabetical)") #This will determine whether or not to order the results in alphabetical order
if order == 'Alphabetical' or 'alphabetical':
    print(sorted(swag))
if order == 'Top' or 'top':
    print(sorted(swag, key=int))

我如何将这些按顺序排序，例如降序？

Answer 1

你必须按数值排序，然后根据你得到的结果，只需将其反转以反转顺序。

这里的关键是通过定义要排序的key参数的函数来按需要排序。

这里的函数是一个lambda，它只返回要排序的字符串的数字部分;它将按升序返回。

要撤消订单，只需撤消列表。

with open(document) as d:
   swag = [line.strip() for line in d if line.strip()]

by_number = sorted(swag, key=lambda x: int(x.split(':')[1]))
descending = by_number[::-1]

Answer 2

您需要在:分割每一行。从名称中删除空格并将数字转换为整数（如果有，则转换为浮点数）。略过空行。

with open(document) as fobj:
    swag = []
    for line in fobj:
        if not line.strip():
            continue
        name, number_string = line.split(':')
        swag.append((name.strip(), int(number_string)))

排序很简单：

by_name = sorted(swag)
by_number = sorted(swag, key=lambda x: x[1])
by_number_descending = sorted(swag, key=lambda x: x[1], reverse=True)

变异

使用itemgetter：

from operator import itemgetter

by_number_descending = sorted(swag, key=itemgetter(1), reverse=True)

按字母顺序和数字排序

2 个答案:

变异