NodeJS - 如何通过执行查询获取mysql结果？

Question

我是NodeJS的新手mysql（npm install mysql）。

当我尝试执行像

这样的查询时

connection.query("select ?? from users where id = ?",[["id","fname","lname"],req.body.userid],function (err, rows) {
     **here I want query which above executed**
});

我想在执行的回调函数中查询。

我怎样才能得到它？。

Answer 1

var c = connection.query("select ?? from users where id = ?",[["id","fname","lname"],req.body.userid],function (err, rows) {
     console.log(c.sql)
});

Answer 2

connection.query("select ?? from users where id = ?",[["id","fname","lname"],req.body.userid],function (err, rows) {
     res.send(rows);
});

还优先将字符串查询转换为：

"select id,fname,lname from users where id = '"+req.body.userid+"'"