Question

我必须使用RxSwift

启用基于两个文本字段上的字符数的按钮

@IBOutlet weak var userTextField: UITextField!
@IBOutlet weak var passwordTextField: UITextField!
@IBOutlet weak var buttonToEnableDisable: UIButton!

var enabledObservable = combineLatest(userTextField.rx_text, passwordTextField.rx_text) 
{ (user,password) in
   self.loginButton.enabled = a.characters.count > 0 && b.characters.count > 0
}

最后我通过这样做来完成，但我不确定它是否是最佳方式：

    _ = combineLatest(emailTextField.rx_text, passwordTextField.rx_text) { (a: String, b:String) in
        self.loginButton.enabled = (a.characters.count > 0 && b.characters.count > 0)
    }.subscribeNext { (result) -> Void in
    }

编辑最终版本：

    _ = combineLatest(emailTextField.rx_text, passwordTextField.rx_text) { (a: String, b:String) in
        return (a.characters.count > 0 && b.characters.count > 0)
        }.subscribeNext { enabled in
            self.loginButton.alpha = enabled ? 1 : 0.5
            self.loginButton.enabled = enabled
        }
        .addDisposableTo(disposeBag)

Answer 1

如果我理解正确，你可能想要这样的东西

  let loginValidation = loginTextFiled
     .rx_text
     .map({!$0.isEmpty})
     .shareReplay(1)

  let userNameValidation = passwordTextField
     .rx_text
     .map({!$0.isEmpty})
     .shareReplay(1)

  let enableButton = combineLatest(loginValidation, userNameValidation) { (login, name) in
     return login && name
  }

  enableButton
     .bindTo(loginButton.rx_enabled)
     .addDisposableTo(disposeBag)

有关详情，建议您查看RxExamples

在那里你可以找到很多常见问题的答案。玩得开心=）

Answer 2

在RxSwift最新版中

let nameValidation = self.userNameTxtFld
    .rx.text
    .map({!($0?.isEmptyString())!})
    .share(replay: 1)

    let pwdValidation = passwdTxtFld
        .rx.text
    .map({!($0?.isEmptyString())!})
    .share(replay: 1)


    let enableButton = Observable.combineLatest(nameValidation, pwdValidation) { $0 && $1 }
        .share(replay: 1)

    enableButton
        .bind(to: loginBtn.rx.isEnabled)
        .disposed(by: disposeBag)

RxSwift：基于文本字段的启用/禁用按钮不为空

2 个答案: