消除PHP

Question

$ticket_details =  Array ( 
    18271 => Array ( 
        0 => Array ( 
            0 => 'Aziz',
            1 => '2010-10-20 08:12:53' 
        ),
        1 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-10-20 10:10:10' 
        ),
        2 => Array ( 
            0 => 'Aziz',
            1 => '2010-10-20 11:54:57' 
        ) ,
        3 => Array ( 
            0 => 'gemma' ,
            1 => '2010-10-20 23:47:41' 
        ) ,
        4 => Array ( 
            0 => 'gemma' ,
            1 => '2010-11-01 08:40:20' 
        ) ,
        5 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 10:00:44' 
        ) ,
        6 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 11:21:55' 
        )  ,
        7 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 11:21:55' 
        )  ,
        8 => Array ( 
            0 => 'gemma' ,
            1 => '2010-11-03 11:21:55' 
        )  ,
        9 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 11:21:55' 
        ) 
    ) 
);

我想删除第0个元素的连续值。 假设：'Aziz'连续3次出现。我想保留其中任何一个。 'gemma'再次连续出现2次。我想采取这两个中的任何一个。

输出应该是这样的：

$ticket_details =  Array ( 
    18271 => Array ( 
        0 => Array ( 
            0 => 'Aziz',
            1 => '2010-10-20 08:12:53' 
        ),
        1 => Array ( 
            0 => 'gemma' ,
            1 => '2010-11-01 08:40:20' 
        ) ,
        2 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 11:21:55' 
        )  ,
        3 => Array ( 
            0 => 'gemma' ,
            1 => '2010-11-03 11:21:55' 
        )  ,
        4 => Array ( 
            0 => 'Aziz' ,
            1 => '2010-11-03 11:21:55' 
        ) 
    ) 
);

我试过这些代码。但它仅适用于第一个连续值。不适用于其他价值观。

    foreach ($ticket_details[18271] as $key => $value) {
            if (isset($ticket_details[18271][$key+1])) {

                if ($ticket_details[18271][$key][0] == $ticket_details[18271][$key+1][0]) {
                    $temp[$y] = $ticket_details[18271][$key+1][0];                      
                } else {
                    $temp[$y] = $ticket_details[18271][$key+1][0];
                }
                if (isset($temp[$y-1]) && (($ticket_details[18271][$key-1][0] == $ticket_details[18271][$key][0]) && 
                    ($ticket_details[18271][$key][0] == $ticket_details[18271][$key+1][0]))) {
                    $y = $y-1;
                    $temp[$y] = $ticket_details[18271][$key+1][0];
                }
            }

            $y++;
        }


        print_r($temp);

Answer 1

只需跟踪使用的姓氏。

$temp = array();
$last_name_stored=''; // To keep track of last saved item
foreach ($ticket_details[18271] as $key => $value) {
    if ($value[0] != $last_name_stored){ // check if already used
        $temp[18271][] = $value;
        $last_name_stored = $value[0]; // update the last saved item
    }
}

print_r($temp);