Question

（标题问题）

例如：

FILEA：

this is a
that was a

档案B：

that was a school
hi, you should ignore me
this is a example
that was a sample
...

我们想要的是在第三个文件中包含文件B的行1,3,4，（...）的文件。任何只有bash命令的解决方案？答案使用命令行＆＃34; Perl＆＃34; （如有必要）也可以提供帮助。

Answer 1

使用awk你可以这样做：

awk 'NR==FNR{arr["^" $1]; next} {for (line in arr) if ($0 ~ line) {print; break}}' fileA fileB
that was a school
this is a example
that was a sample

首先，我们阅读fileA并构建一个数组^（行开头）与fileA的每一行连接在一起。然后在浏览fileB时，我们只需遍历arr并打印匹配的任何行。

Answer 2

使用命令行Perl：

$ perl -ne '
    BEGIN {
        local @ARGV = shift;
        $pat = join "|", map {chomp; quotemeta} <>;
    }
    print if /$pat/
    ' filea fileb

输出：

that was a school
this is a example
that was a sample

Answer 3

在Perl脚本中：

use warnings;
use strict;

my ($file1, $file2) = qw(file1.txt file2.txt);

open my $fh1, '<', $file1 or die "Can't open $file1: $!";
open my $fh2, '<', $file2 or die "Can't open $file2: $!";

my @compline = <$fh2>;
chomp @compline;

while (<$fh1>)
{
    chomp $_;
    foreach my $line (@compline)
    {
        if ($line =~ m/^$_/)
        {
            print "$line\n";
        }
    }
}

输出：

this is a example
that was a school
that was a sample

如何从文件B中提取所有以bash中的FileA＆line文件串开头的行？

3 个答案: