Question

我有一个重叠预订日期的临时表。这些日期可以以任何方式组合重叠，因为它们适用于多个可用房间。

我想创建一个返回一组合并日期的查询。（结帐日期是可用日期。）

例如，以下数据

+--------+-------------+------------+------------+
| id     | rental_unit | checkin    | checkout   |
+--------+-------------+------------+------------+
|   9144 |         224 | 2015-11-04 | 2015-12-27 |
| 352580 |         341 | 2015-12-01 | 2016-02-06 |
|   7519 |         224 | 2015-12-27 | 2016-01-05 |
|   9141 |         224 | 2016-01-05 | 2016-02-04 |
|  13834 |         341 | 2016-01-16 | 2016-01-23 |
|   9142 |         224 | 2016-02-05 | 2016-03-04 |
| 352581 |         341 | 2016-02-07 | 2016-03-12 |
|  11707 |         341 | 2016-02-22 | 2016-03-12 |
|  11239 |         224 | 2016-03-11 | 2016-03-19 |
|  11889 |         224 | 2016-03-20 | 2016-04-03 |
| 352582 |         341 | 2016-03-27 | 2016-04-07 |
+--------+-------------+------------+------------+

会回来：

+------------+------------+
| checkin    | checkout   |
+------------+------------+
| 2015-11-04 | 2016-03-19 |
| 2016-03-20 | 2016-04-07 |
+------------+------------+

谢谢！

Answer 1

两个内部查询确定每组日期范围的签入和签出日期（上面的示例数据集中有2个）。我将这两组日期连接在一起，外部查询获得您想要的签入/结帐日期组合。

SELECT t2.checkin, MIN(t1.checkout) FROM
(
    SELECT b1.checkout AS checkout
    FROM bookings b1 INNER JOIN bookings b2 ON b1.checkout BETWEEN b2.checkin AND b2.checkout
    GROUP BY b1.checkout
    HAVING COUNT(*) = 1
) t1
INNER JOIN
(
    SELECT b1.checkin AS checkin
    FROM bookings b1 INNER JOIN bookings b2 ON b1.checkin BETWEEN b2.checkin AND b2.checkout
    GROUP BY b1.checkout
    HAVING COUNT(*) = 1
) t2
ON t2.checkin < t1.checkout
GROUP BY t2.checkin

点击以下链接查看正在运行的演示：

SQLFiddle

MySQL合并表记录与重叠日期跨度

1 个答案: